C that is your answer hope this helps
Answer:
f_tympanum = 256 Hz.
Explanation:
The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.
Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency
f_tympanum = 256 Hz.
As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz
Answer:
The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Explanation:
Given that,
Atomic number = 20
The configuration of Ca
So, The principle quantum number is n =4.
The azimuthal quantum number can take value from 0,1,2...(n-1)
In the ground state, l= 0
When it is excited to p state
Then, l = 1
The magnetic quantum number can take value from l to -l
Hence, The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Answer:
KE + PE = KE + PE
Explanation:
In a closed system, the mechanical energy of the system is constant.
Mechanical energy is given by the sum of kinetic energy and potential energy; mathematically:
U = KE + PE
where
KE is the kinetic energy
PE is the potential energy
This means that if we consider two situations, one at the beginning and one at the end, the value of U will not change if the system is closed; this means that the sum KE + PE will remain the same, so we can write:
KE + PE = KE + PE
