Answer: 355.49
Step by Step:
82.14+9.77+31.35+41.25=164.51
520-164.51=355.49
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
60%, 900/1500 would be .6 and in terms of percent would be 60.
Answer:
Whatever the length and width of the first triangle are take them and multiply by three. Place them in their respective sides of the new rectangle. The answer should be 9.
Step-by-step explanation:
Answer:
BE is congruent to ED
Step-by-step explanation:
