basically x=something is the axis of symmetry the way to find the axis of symmetry is to convert to vertex form and find h and that's the axis of symmetry
but there's an easier way
for f(x)=ax^2+bx+c the axis of symmetry is x=-b/2a nice hack my teacher taught me
so
f(x)=3x^2+0x+0 axis of symmetry is -0/(3*2), so x=0 is the axis of symmetry for f(x)
g(x)=1x^2-4x+5, axis of symmetry is -(-4)/(2*1)=4/2=2, x=2 is axis of symmetry for g(x)
h(x)=-2x^2+4x+1 axis of symmetry is -4/(2*-2)=-4/-4=1, x=1 is the axis of symmetry for h(x)
0<1<2 axisies f(x)<h(x)<g(x)
order based on their axises of symmetry is f(x), h(x), g(x)
Since one of the angles is 90 degrees (right angle) and the other two angles are less than 90 degrees (acute angles) it is a right triangle because it cousins of right angle. Hope this helped!