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Shkiper50 [21]
3 years ago
9

Given functions f(x)=3x^2, g(x)= x^2-4x+5, and h(x)=-2x^2+4x+1 Rank them from least to greatest

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0
Ok, ranked by axis of symmetry

basically x=something is the axis of symmetry
the way to find the axis of symmetry is to convert to vertex form and find h and that's the axis of symmetry

but there's an easier way

for f(x)=ax^2+bx+c
the axis of symmetry is x=-b/2a
nice hack my teacher taught me


so

f(x)=3x^2+0x+0
axis of symmetry is -0/(3*2), so x=0 is the axis of symmetry for f(x)

g(x)=1x^2-4x+5,
axis of symmetry is -(-4)/(2*1)=4/2=2, x=2 is axis of symmetry for g(x)


h(x)=-2x^2+4x+1
axis of symmetry is -4/(2*-2)=-4/-4=1, x=1 is the axis of symmetry for h(x)


0<1<2
axisies
f(x)<h(x)<g(x)

order based on their axises of symmetry is f(x), h(x), g(x)
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Write an equation: The sides of a rectangle are x and ( x - 4 ). The perimeter is 87
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So just put these values into:  perimeter = 2 × width + 2 × length:

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_____________________________

Answer:

The equation is:       87 = 2(x) + 2(x - 4)

<em>(note: this can be simplified down like so:</em>

<em>87 = 2x + 2x - 8</em>

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<em>95 = 4x</em>

23.75 = x    

)

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