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BartSMP [9]
3 years ago
7

The y-variable is the value that tells us to move in what direction on a graph?

Mathematics
1 answer:
kompoz [17]3 years ago
6 0
It is 3y because of the calculation being equivalent
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9/16= what to the power of 2
Damm [24]
The answer to this is 3/4.
3 0
3 years ago
A package of four bottles of a sports drink cost $5.28. what is the cost per bottle
Dafna1 [17]
$1.32 per bottle because you would divide $5.28 into 4 and get $1.32
3 0
3 years ago
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Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi
Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ;  2Bs and 3Cs it is possible to get a palindrome if you fixed the  letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

<u>C</u> (       ) <u>C</u> (       ) <u>C</u>

To fill in the gaps we have  4 letters  A and 2 letters B, wich we have two divide in two palindrome gaps,  

AAB         and    BAA the palindrome is  C  AAB C BAA C

BAA         and    AAB    "           "           is  C  BAA C AAB C  

ABA         and    ABA    "           "           is  C  ABA C ABA C

b) 4 A  ;   2B  ; 3C

We have the total number of elements  9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A  ; 2 B  ; 2C  : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0
3 years ago
Need help with 9 and 12(theirs a picture)
Doss [256]

Number 6 is incorrect. Remember when you see -(-1) that is addition because you are subtracting a negative from a negative so you take the negative sign away and you have a positive. The correct answer to 6 is -75. For number 9 the first thing that you are gonna do is distribute that negative sign to the -12 in parentheses. This will make it a positive 12 which leaves you with

-8+12-31=-27

Next for number 12 you will distribute the - sign onto the -9 in parentheses and the -16 in parentheses. This will leave you with -16+9+16=9

Hope that this helped!

8 0
3 years ago
What would the answer be to the expression 22 + (30 - 4) ÷2
Alex

Answer:

24

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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