first, is 4 to the power of 2=16 and now we are going to put the x back into the equation so: 4x to the power of 2, but we did the exponents so, now x is the missing number. We can use the 32 because it is the solution to the equation. So we would do 32-16=16 so the missing number is 16 so x=16

Answer: x=16

4 0

3 years ago

The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance b

Dima020 [189]

Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug in the numbers:
${4}^{2} + {3}^{2} = {c}^{2} \\ \\ = 16 + 9 \\ \\ = 25 \\ \\ c = \sqrt{25} = 5$
c is 5.

Same thing with g:
${e}^{2} + {f}^{2} = {g}^{2} \\ \\ {g}^{2} = {4}^{2} + {4}^{2} \\ \\ = 16 + 16 \\ \\ = 32 \\ \\ g = \sqrt{32} = 4 \sqrt{2} = 5.66$
g equals 5.66.

7 0

4 years ago

5+68empty space, 5, plus, 68 =(3+=(3+equals, left parenthesis, 3, plus 5 )+ 68)+68right parenthesis, plus, 68 =3 + (=3+(equals,

hoa [83]

Answer:

Give me and example

Step-by-step explanation:

6 0

3 years ago