Answer:
Option (A)
Step-by-step explanation:
From the figure attached,
By applying triangle sum theorem in ΔBCP,
m∠CBP + m∠CPB + m∠BCP = 180°
15° + 20° + m∠BCP = 180°
m∠BCP = 145°
m∠ACB + m∠BCP = 180° [Linear pair of angles are supplementary]
m∠ACB + 145° = 180°
m∠ACB = 35°
Since, ∠ACB is the inscribed angle and AB is the intercepted arc.
Therefore, m(arc AB) = 2m(∠ACB)
m(arc AB) = 2 × 35°
= 70°
Therefore, Option (A) is the correct option.
Answer:
Correct Answer is A. 3 times root 5.
Step-by-step explanation:
We all know that in a right angled triangle, the square of both sides is equal to the square of hypotension.
hence,
a^2 + b^2 = c^2
a^2 + (2)^2 = (7)^2
a^2 + 4 = 49
a^2 = 49-4
a^2 = 45
a = root of 45 which is 6.7082
which can be written as 3 times root 5
C - 7.2 = (11.6 - 7.2)/(9 - 4) (d - 5)
c - 7.2 = 4.4/4 (x - 5) = 1.1(d - 5)
c = 1.10d - 5.5 + 7.2
c = 1.10d + 1.70
The last option is correct.
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575
</span> For the domain we have:
<span> </span>We match zero:
-4.92t ^ 2 + 17.69t + 575 = 0
We look for the roots:
t1 = -9.16
t2 = 12.76
We are left with the positive root, so the domain is:
[0, 12.76]
For the range we have:
We derive the function:
h '(t) = - 9.84t + 17.69
We equal zero and clear t:
-9.84t + 17.69 = 0
t = 17.69 / 9.84
t = 1.80
We evaluate the time in which it reaches the maximum height in the function:
h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
h (1.80) = 590.90
Therefore, the range is given by:
[0, 590.9]
Answer:
the domain and range are:
domain: [0, 12.76] range: [0, 590.9]
Answer:
True
Step-by-step explanation:
- Solve what's in parentheses: -3 + 1 = -2, 4 - 8 = -2
- Plug -2 and -2 in: 11 + 5(-2) - 2 = -(-2) - 5
- Simplify: 11 + 5(-2) - 2 = 2 - 5
- 5 × -2 = -10
- Plug -10 in: 11 + -10 - 2 = 2 - 5
- 2 - 5 = -3
- Plug -3 in: 11 + -10 - 2 = -3
- 11 + -10 = 1
- Plug 1 in: 1 - 2 = -3
- 1 - 2 = -3, so we know it's correct
I hope this helps!