The expression 3n^2 can be separated into (3n)(n).
Factored formula is in the form (a+b)(a+b), where b*b is equal to the last term in the expression, 15. The factors of 15 are three and five.
Using these two piece of information, we know it must be either (3n+3)(n+5) or (3n+5)(n+3). To get the middle term, 14n, using FOIL, this is equivalent to ((3n)(3) + (5)(n)) in the latter expression. In the first expression, ((3n)(5) + (3)(n)) = 18n, which is not equivalent to the given equation’s middle term.
Therefore, we know that the factored form of this equation is (3n+5)(n+3).
The solutions, or zeroes, of any equation are where y=0. Therefore, we set the expression 3n^2+14n+15=0, or (3n+5)(n+3)=0. To obtain zero from two products, either of the products must equal zero. Therefore, we can state 3n+5=0 and n+3=0. Solving these equations, we get:
3n+5=0
3n=-5
n=-5/3
and
n+3=0
n=-3.
Finally, the solutions are n=-5/3 and n=-3
The formula to calculate the missing arc is,
where,
Therefore,
Hence, the answer is
Let
x-------> the length of the base one
y------> the length of the base two
we know that
area of an trapezoid=[x+y]*h/2----> 2*A/h=x+y----> y=[2*A/h]-x
area=80 cm²
x=8 cm
h=8 cm
y=?
y=[2*A/h]-x----> y=[2*80/8]-8-----> y=12 cm
the answer is
<span>the length of the other base is 12 cm</span>
Answer:
f(-2) = 4
Step-by-step explanation:
f(x) = x²
f(-2) = (-2)² = (-2)(-2) = 4
Answer:
No, it is not.
Step-by-step explanation:
The set 
contains every ordered pair of Natural numbers, while B only contains those pairs in which both values in each entry are the same. Therefore, C is a bigger set than B, but B is not equal to C because for example C contains ![[1] \times [2]](https://tex.z-dn.net/?f=%5B1%5D%20%5Ctimes%20%5B2%5D%20)
and B doesnt because 1 is not equal to 2.
