It would take <u> 8 years </u> for the asteroid to orbit once around the sun.
What is a semimajor axis?
- In geometry, the major axis of an ellipse is its longest diameter: a line segment that runs through the center and both foci, with ends at the two most widely separated points of the perimeter.
- The semi-major axis (major semiaxis) is the longest semidiameter or one half of the major axis, and thus runs from the centre, through a focus, and to the perimeter.
- The semi-major axis of a hyperbola is, depending on the convention, plus or minus one half of the distance between the two branches.
- Thus it is the distance from the center to either vertex of the hyperbola.
- In astronomy, the semi-major axis is one of the most important orbital elements of an orbit, along with its orbital period.
- For Solar System objects, the semi-major axis is related to the period of the orbit by Kepler's third law.
To know more about semi-major axis, refer:
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Answer:
Objects with mass exert forces on each other via the force of gravity. This force is proportional to the mass of the two interacting objects, and is inversely proportional to the square of the distance between them. The factors G, M, and r are the same for all masses at the surface of the Earth.
Answer:
Ohms law
Explanation:
Which states that the current flowing through any cross-section of the conductor is directly proportional to the potential differenceapplied across its end, provided physical conditions like temperature and pressure remain constant.
Answer ) Sound level equation
The intensity of a sound wave is related to its amplitude squared by the following relationship: I=(Δp)22ρvw I = ( Δ p ) 2 2 ρ v w . Here Δp is the pressure variation or pressure amplitude (half the difference between the maximum and minimum pressure in the sound wave) in units of pascals (Pa) or N/m2.
<h2>
The asteroid is 4.11 x 10¹¹ m far from Sun</h2>
Explanation:
We have gravitational force
Where G = 6.67 x 10⁻¹¹ N m²/kg²
M = Mass of body 1
M = Mass of body 2
r = Distance between them
Here we have
M = Mass of Sun = 1.99×10³⁰ kg
m = Mass of asteroid = 4.00×10¹⁶ kg
F = 3.14×10¹³ N
Substituting
The asteroid is 4.11 x 10¹¹ m far from Sun
