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swat32
3 years ago
9

1. Do the particles in the medium material move in the same direction of the wave or at opposite direction to the wave? Explain

your answer.
2. By inputting more energy into the wave, i.e a large shake of the spring, which wave property also increases?

3. Are there forces of friction acting while a wave is passing through a medium?
Physics
1 answer:
juin [17]3 years ago
7 0

1. Both

Assuming we are talking about a longitudinal wave (where particles oscillate in a direction parallel to the direction of motion of the wave), the answer is 'both'. In fact, waves consist of oscillations of the particles of a medium: in the case of the longitudinal waves, the particles oscillate back and forth, back and forth, continuosuly. This means that at some time they are moving forward, while at some time they are moving backward, with respect to the direction of the wave.


2. The amplitude

The energy of a wave is related to its amplitude. More specifically, the energy of a wave is proportional to the square of its amplitude:

E\propto A^2

therefore, if the spring has a larger amplitude of oscillation, it also has more energy.


3. Yes

Forces of friction act while a mechanical wave passes through a medium. As a result, particles during the oscillations lose part of their energy: this means that the amplitude of the oscillations of the wave decrease over time, because the wave loses some energy. Eventually, if the friction lasts enough, the wave can lose all its energy.

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A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors
Mars2501 [29]

Answer:

(A) Capacitance per unit length = 4.02 \times 10^{-10}

(B) The magnitude of charge on both conductor is Q = 4.22 \times 10^{-19} C and the sign of charge on inner conductor is +Q and the sign on outer conductor is -Q

Explanation:

Given :

Radius of inner part of conductor  (R_{1}) = 2.7 \times 10^{-3} m

Radius of outer part of conductor  (R_{2}) = 3.1 \times 10^{-3} m

The length of the capacitor (l) = 3 \times 10^{-3} m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,      

     C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }

Where, \epsilon_{o} = 8.85 \times 10^{-12}

But we need capacitance per unit length so,

     \frac{C}{l}  = \frac{2\pi\epsilon_{o}  }{ln\frac{R_{2} }{R_{1} } }

capacitance per unit length = \frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}

(B)

The charge on both conductors is given by,

     Q = C \Delta V

Where, C = capacitance of cylindrical capacitor and value of C = 12.06 \times 10^{-13} F, \Delta V = 350 \times 10^{-3} V

∴ Q = 4.22 \times 10^{-19} C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is +Q and Charge on outer conductor is -Q.

8 0
3 years ago
What is the velocity of a car that travels 1,069 meters in 54 seconds?
irga5000 [103]

Answer:

20.41m/s. hdjdgshd

Explanation:

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3 years ago
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PLEASE HELP WILL GIVE BRAINLIEST!!!
Elan Coil [88]

The spring constant is 181.0 N/m

Explanation:

We can solve the problem by applying the law of conservation of energy. In fact, the elastic potential energy initially stored in the compressed spring is completely converted into gravitational potential energy of the dart when the dart is at its maximum height. Therefore, we can write:

\frac{1}{2}kx^2 = mgh

where the term on the left represents the elastic potential energy of the spring while the term on the right is the gravitational potential energy of the dart at maximum height, and where

k is the spring constant of the spring

x = 2.08 cm = 0.0208 m is the compression of the spring

m = 12.3 g = 0.00123 kg is the mass of the dart

g=9.8 m/s^2 is the acceleration due to gravity

h = 3.25 m is the maximum height of the dart

Solving for k, we find:

k=\frac{2mgh}{x^2}=\frac{2(0.00123)(9.8)(3.25)}{(0.0208)^2}=181.0 N/m

Learn more about potential energy:

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3 years ago
Which component of a galaxy consists of tiny particles that look smoky or cloudy and
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Answer:

Cosmic dust

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If you wanted to live where the chances of a destructive earthquake were small, would you pick a location near a fault zone, nea
exis [7]

Answer: A volcanic island arc like Hawaii.

Explanation: The Hawaiian island is the most safest place for the people to live in comparison to the other given options.

The plate tectonic movement generates energy due to collision, resulting in sudden release of energy, and seismic waves are produced that propagates and causes earthquake.

Due to the constant collision between the plates, different places at different time experiences earthquake. Near a fault region, earthquakes are very severe, and also near the mid oceanic ridge it is not possible for a person to live. The subduction zones are the region where a denser plate subducts beneath the other, and its impossible for life to exist there.

Thus the most safest place out of all the option is the volcanic islands where numerous people resides. for example, the Hawaiian and Stromboli.

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