1. Do the particles in the medium material move in the same direction of the wave or at opposite direction to the wave? Explain
1 answer:
1. Both
Assuming we are talking about a longitudinal wave (where particles oscillate in a direction parallel to the direction of motion of the wave), the answer is 'both'. In fact, waves consist of oscillations of the particles of a medium: in the case of the longitudinal waves, the particles oscillate back and forth, back and forth, continuosuly. This means that at some time they are moving forward, while at some time they are moving backward, with respect to the direction of the wave.
2. The amplitude
The energy of a wave is related to its amplitude. More specifically, the energy of a wave is proportional to the square of its amplitude:
therefore, if the spring has a larger amplitude of oscillation, it also has more energy.
3. Yes
Forces of friction act while a mechanical wave passes through a medium. As a result, particles during the oscillations lose part of their energy: this means that the amplitude of the oscillations of the wave decrease over time, because the wave loses some energy. Eventually, if the friction lasts enough, the wave can lose all its energy.
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The initial speed of the shot is 15.02 m/s.
The Shot put is released at a height y<em> </em>from the ground with a speed u. It is released at an angle θ to the horizontal. In a time t, the shot put travels a distance <em>R</em> horizontally.
Pl refer to the attached diagram.
Resolve the velocity u into horizontal and vertical components, u ₓ=ucosθ and uy=u sinθ. The horizontal component remains constant in the absence of air resistance, while the vertical component varies due to the action of the gravitational force.
Write an expression for R.
Therefore,
In the time t, the net displacement of the shotput is y in the downward direction.
Use the equation of motion,
Substitute the value of t from equation (1).
Substitute -2.10 m for y, 24.77 m for R and 38.0° for θ and solve for u.
The shot put was thrown with a speed 15.02 m/s.
Given,
Effort force = 120 N
Load force= 1050 N
Mechanical advantage of a pulley is given by the ratio of load force to the effort force.
Therefore, the mechanical advantage of the given pulley is 8.75.
Answer:
Explanation:
Given
Cannon is fired with a velocity of
Using Equation of motion
where
after time
So after 3.3 s cannon ball is at a height of 185.89 m