Explanation:
power = 1/2 mass × velocity^2 >>1
velocity = distance / time = 76 /18 = 4.2m
then power = 1/2 × 276 × (4.2)^2 = 138 × 17.64 = 2,434.3 jules.
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We use the binomial theorem to answer this question. Suppose we have a trinomial (a + b)ⁿ, we can determine any term to be:
[n!/(n-r)!r!] a^(r) b^(n-r)
a.) For x⁵y³, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.
r = 5
n - r = 3
Solving for n,
n = 3 + 5 = 8
Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-5)!8! = 56
b.) For x³y⁵, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.
r = 3
n - r = 5
Solving for n,
n = 5 + 3 = 8
Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-3)!8! = 56
Answer:
The mass flow rate of air is 0.732 kg/s.
The velocity at the exit is 5.927 m/s.
Explanation:
Given that,
Diameter = 28 cm
Enter pressure= 200 kPa
Enter temperature = 20°C
Velocity = 5 m/s
Exit pressure = 180 kPa
Exit temperature = 40°C
We need to calculate the mass flow rate of air
Using formula of mass flow rate
Put the value into the formula
We need to calculate the volume flow rate
Using formula of volume flow rate
We need to calculate the velocity at the exit
Using formula of velocity
Put the value into the formula
Hence, The mass flow rate of air is 0.732 kg/s.
The velocity at the exit is 5.927 m/s.
