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rodikova [14]
4 years ago
11

Which surface has more friction A. an ice rinkB. a grassy field C. a paved road​

Physics
1 answer:
antoniya [11.8K]4 years ago
4 0

Answer:

<h2>The answer is </h2><h2>C. a paved road</h2>

Explanation:

Generally, roads are meant to have very rough surfaces to allow for friction between car tyres hence the motion of vehicles.

What is a paved surface?

Paved roads are roads that are covered with a firm surface suitable for travel, like paving stones or concrete or asphalts.

Another good example of a paved road is a  small paved courtyard, covered with a hard layer of concrete/cement.

The other two examples sited in this problem are glossy materials with very low surface friction, that is their surfaces are very smooth.

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The Cassegrain design provides more compact (shorter) telescopes. Why? (Examine figures 2.4.2 and 2.4.3). The shorter design is
Ipatiy [6.2K]

Answer:

Because the light reflects multiple times until it gets to the Cassegrain focus.

Explanation:

The Cassegrain design can be seen in a reflecting telescope. In this type of design the light is collected by a concave mirror, and then intercepted by a secondary convex mirror, and sends it down to a central opening in the primary mirror (concave mirror), in which a detector is placed (Cassegrain focus)

Since, the light is reflected many times due to Cassegrain design, that leads to shorter telescopes.                    

5 0
3 years ago
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to
aev [14]

Answer:

D. Test a cell phone's reception in the exact same location under various atmospheric conditions

Explanation:

Components of an experiment:

Independent variable:

A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the  dependent variable.

Dependent variable:

A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.

Control variable:

Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.

In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.

Hence, the best option is D.

4 0
4 years ago
What does a tree do to maintain homeostasis during the winter months?
grin007 [14]

Answer:

During dormancy, a tree's metabolism, energy consumption, and growth all slow down significantly in order to endure the harsh season of winter when water and sunlight are more scarce.

Explanation:

hope it helps

mark me brainliest pls

6 0
3 years ago
TIME REMAINING
rusak2 [61]

Answer:

The total energy in the system remains the same as the decrease in chemical energy equals the increase in thermal and  radiant energy

Explanation:

According to the law of conservation of energy, "energy cannot be created nor destroyed, but only transformed".

This means that for an isolated system, the total energy of the system must remain constant.

In this case, the total energy of the system (the battery and the lightbulb) is the sum of 3 components:

- Chemical energy of the battery

- Thermal energy (the heat produced by the light bulb)

- Radiant energy (the light emitted by the bulb)

The sum of these 3 components of energy must be constant.

At the beginning, all the energy is stored as chemical energy inside the battery. Later, this energy is converted into electrical energy first (when the current starts circulating through the circuit), and finally, this energy is entirely converted into thermal energy and radiant energy as heat and light emitted by the bulb.

4 0
4 years ago
Read 2 more answers
A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the
max2010maxim [7]

Answer:

V = 381.70 m³

Explanation:

ρ air = 1.28 kg / m³

ρ helium = 0.18 kg / m³

R = 4.5 m

Vb = 0.068 m³

mb = 123 kg

To determine the volume of helium in the balloon when fully inflated

V = 4 / 3 π * R ³

V = 4 * π / 3 ( 4.5 m )³

V = 381.70 m³

To determine the mass total

m = ρ helium * V

m = 0.18 kg / m³  * 381.70  m³

m = 68.70 kg

mt = ( 68.70 + 123 )kg

mt = 191.70 kg

3 0
4 years ago
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