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rodikova [14]
3 years ago
11

Which surface has more friction A. an ice rinkB. a grassy field C. a paved road​

Physics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

<h2>The answer is </h2><h2>C. a paved road</h2>

Explanation:

Generally, roads are meant to have very rough surfaces to allow for friction between car tyres hence the motion of vehicles.

What is a paved surface?

Paved roads are roads that are covered with a firm surface suitable for travel, like paving stones or concrete or asphalts.

Another good example of a paved road is a  small paved courtyard, covered with a hard layer of concrete/cement.

The other two examples sited in this problem are glossy materials with very low surface friction, that is their surfaces are very smooth.

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A large elliptical galaxy

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A ball is released from a tower at a height of 100 meters toward the roof of another tower that is 25 meters high. The horizonta
I am Lyosha [343]
-- During the time the ball is flying from the high roof to the low roof,
it's going to fall (100-25) = 75 meters.
How long does it take an object dropped from rest to fall 75 meters ?

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75 m = (4.9 m/s²) · (time)²

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6 0
11 months ago
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
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