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KATRIN_1 [288]
3 years ago
15

1. Two wires - A and B - with circular cross-sections have identical lengths and are made of the same material. Yet, wire A has

four times the resistance of wire B. How many times greater is the diameter of wire B than wire A?
Physics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

Diameter of wire B is 2 times the diameter of wire A

Explanation:

We have given two wire A and B

They are made up of same material and length of both the wire is sane

So l_A=l_B

Let the resistivity of both the wire is \rho

It is given that wire A has 4 times the resistance as wire B

So R_A=4R_B

So \frac{\rho l_A}{a_A}=4\frac{\rho l_B}{a_B} ( As l_A=l_B )

\frac{a_A}{a_B}=\frac{1}{4}

\frac{d_A^2}{d_B^2}=\frac{1}{4}

\frac{d_A}{d_B}=\frac{1}{2}

d_B=2d_A

So diameter of wire B is 2 times the diameter of wire A

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What is measurement ?​
Akimi4 [234]

Answer:

Measurement is the assignment of a number to a characteristic of an object or event

Explanation:

6 0
3 years ago
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In both the camera and the __________, light enters a narrow opening and is projected onto a photosensitive surface. Group of an
Citrus2011 [14]

Answer: The HUMAN EYE

Explanation:

The human eye is made up of different parts which ranges from controlling the amount of light that enters the eye to the focusing of the image that is formed. The camera is a device which is both mechanically and electronically operated which shares a number of similarities with the eye.

In the human eye, the IRIS helps to regulate the amount of rays passing through the pupil to the lens by either contracting or dilating in light or dark environment respectively. While in the camera, the DIAPHRAGM controls the amount of light entering the camera.

The PUPIL serves as the passage for light into the eye while in the camera, the APERTURE does the same.

The photosensitive surface in the eye is the YELLOW SPOT while in the camera, the photosensitive surface is the PHOTOGRAPHIC FILM.

5 0
3 years ago
Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. The
AnnyKZ [126]

Answer:

Fy=107.2 N

Explanation:

Conceptual analysis

For a right triangle :

sinβ = y/h formula (1)

cosβ = x/h formula (2)

x: side adjacent to the β angle

y:  opposite side of the β angle

h: hypotenuse

Known data

h = T = 153.8 N : rope tension

β= 44.2°with the horizontal (x)

Problem development

We apply the formula (1) to calculate Ty : vertical component of the rope force.

sin44.2° = Ty/153.8 N

Ty = (153.8 N ) *(sen44.2°)= 107.2 N  directed down

for equilibrium system

Fy= Ty=107.2 N

Fy=107.2 N upward component of the force acting on the stake

8 0
3 years ago
Suppose we take a 1 m long uniform bar and support it at the 33 cm mark. Hanging a 0.15 kg mass on the short end of the beam res
MakcuM [25]

Answer:

The mass of the beam is 0.074 kg

Explanation:

Given;

length of the uniform bar, = 1m = 100 cm

Set up this system with the given mass and support;

  0-----------------33cm-----------------------------------100cm

  ↓                     Δ                                             ↓      

0.15kg                                                              m

Where;

m is mass of the uniform bar

Apply the principle of moment to determine the value of "m"

sum of anticlockwise moment = sum of clockwise moment

 0.15kg(33 - 0) = m(100 - 33)

0.15(33) = m(67)

m = \frac{0.15kg(33 \ cm)}{67 \ cm}\\\\m = 0.074 \ kg

Therefore, the mass of the beam is 0.074 kg

8 0
3 years ago
it is determined that a certain light wave has a wavelength of 3.012x10^-12 m. the light travels at 2.99x10^8 m/s. what is the f
Dahasolnce [82]

Answer:

9.93\times 10^{19}Hz

Explanation:

Speed of light is the product of its wavelength and frequency, expressed as

S=fw

Where s represent speed, f is frequency while w is wavelength

Making f the subject of the formula then

f=s/w

Substituting 2.99x10^8 m/s for s and 3.012x10^-12 m for w then

f=\frac {2.99\times 10^{8}}{3.012\times 10^{-12}}=9.926958831341\times 10^{19}\\f\approx 9.93\times 10^{19}Hz

Therefore, the frequency equals to 9.93\times 10^{19}Hz

4 0
3 years ago
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