Answer:
Both are only physical changes.
Explanation:
Nothing about the objects chemically change, and they remain the same.
Their changes arent due to heating/cooling.
Answer is: molarity of solution is 0,0951 M.
Chemical reaction: BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl.
m(Na₂SO₄) = 758 mg ÷ 1000 mg/g = 0,758 g.
n(Na₂SO₄) = m(Na₂SO₄) ÷ M(Na₂SO₄).
n(Na₂SO₄) = 0,758 g ÷ 142 g/mol.
n(Na₂SO₄) = 0,00533 mol.
From chemical reaction: n(Na₂SO₄) : n(BaCl₂) = 1 : 1.
n(BaCl₂) = 0,00533 mol.
V(BaCl₂) = 56,0 mL = 0,056 L.
c(BaCl₂) = n(BaCl₂) ÷ V(BaCl₂).
c(BaCl₂) = 0,00533 mol ÷ 0,056 L.
c(BaCl₂) = 0,0951 mol/L.
Sr is the limiting reactant.
Given the reaction equation;
2Sr + O2 (g) → 2SrO
2 moles of Sr reacts with 1 mole of O2
2 moles Sr will react with x mole of O2
x = 2 ×1/2
x = 1 mole of O2
Since we have more O2 than required, it is the reactant in excess, hence Sr is the limiting reactant.
Learn more: brainly.com/question/14225536
Answer:
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive
Explanation:
A wide range of nuclei are found to be NMR active. NMR is the acronym for nuclear magnetic resonance. It is a powerful spectroscopic tool which uses radio waves. The nuclear spin is described by the nuclear quantum number I and can take on values of; 0,1/2, 1, 3/2,2,5/2 etc.
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive e.g Carbon-12 and Oxygen-16 nuclei.
Commonly, all NMR active nuclei posses I ≥ 1/2, Hydrogen -1 , Carbon-13 and boron-11 are common examples of NMR active nuclei.
<span>When two metals touch in the mouth, a small shock is created. this is known as a </span>galvanic action
