The balanced reaction is 2KClO3 --> 2KCl + 3O2
We first divide the 400.0 g KClO3 by the molar mass of 122.55 g/mol to get 3.26 mol KClO3. Next, we use the coefficients: 3.26 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 4.896 mol O2. Multiplying this by the molar mass of 32 g/mol gives 156.67 g O2.
Percent yield = 115.0 g / 156.67 g = 0.734 = 73.40%
This is an acid base reaction which is basically a double displacement reaction. However, since carbonic acid is produced, it rapidly decomposes to carbon dioxide and water.
Answer:
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Explanation:
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
Answer:
Frequency = 0.005× 10¹⁷ s⁻¹
E = 0.03 × 10⁻²⁰KJ
Explanation:
Given data:
Wavelength of light = 630.0 nm (630 × 10⁻⁹ m)
Frequency of light = ?
Energy in joule = ?
Solution:
speed of light = wavelength × frequency
Frequency = speed of light / wavelength
Frequency = 3 × 10⁸ m/s / 630 × 10⁻⁹ m
Frequency = 0.005× 10¹⁷ s⁻¹
Energy:
E = h. f
E = 6.63× 10⁻³⁴ Kg. m²/s × 0.005× 10¹⁷ s⁻¹
E = 0.03 × 10⁻¹⁷ j
E = 0.03 × 10⁻¹⁷ j×1 kj /1000 j
E = 0.03 × 10⁻²⁰KJ