Question

61.0 mol of P4O10 contains how many moles of P

Answer 1

61mol * 4 = 244moles of P

Answer 2

Answer:

244 moles of phosphorus are present in 61.0 moles of $P_4O_{10}$.

Explanation:

Moles of $P_4O_{10}$ = 61.0 moles

1 mol of $P_4O_{10}$ contains 4 moles of phosphorus.

Then 61.0 moles of  $P_4O_{10}$ will contain:

$61.0 mol\times 4=244 mol$ of phosphorus

244 moles of phosphorus are present in 61.0 moles of $P_4O_{10}$.