Answer:
N₂ + 3H₂ → 2NH₃
Explanation:
Chemical equation:
N₂ + H₂ → NH₃
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
Step 1:
N₂ + H₂ → NH₃
left hand side: Right hand side
N = 2 N = 1
H = 2 H = 3
Step 2:
N₂ + 3H₂ → NH₃
left hand side: Right hand side
N = 2 N = 1
H = 6 H = 3
Step 3:
N₂ + 3H₂ → 2NH₃
left hand side: Right hand side
N = 2 N = 2
H = 6 H = 6
Answer:
The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
Answer:
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
% mass Na = (g Na / g H2O) x 100
<span>g Na = (% mass Na)(g H2O) / 100 = (5.2 x 10^-4 g Na / g H2O) </span>
<span>2.4 g Na x (1 g H2O / 5.2 x 10^-4 g Na) = 4600 g Na </span>
<span>4600 g Na x (1 mL H2O / 1 g H2O) = 4600 mL H2O = 4.6 L H2O which is a little more than a gallon</span>
