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andreev551 [17]
3 years ago
8

Carmen buys 153 shares of Cawh Consolidated Banks, each of which pays a constant yearly dividend of $7.14. After six years, how

much has Carmen received in dividends?
a. $5,783.40
b. $1,820.70
c. $1,092.42
d. $6,554.52
Mathematics
2 answers:
Flauer [41]3 years ago
5 0
<span>After 6 years of having 153 shares of Cawh Consolidated Banks, each of which pays a constant yearly dividend of $7.14, the value Carmen will receive in dividends is d. $6,554.52. This is the yearly dividend, so the value each of shares pays after 6 years is: $7.14 * 6 = $42.84. There are 153 shares and since each pays $42.84 after 6 years, the total value for all 153 shares after 6 years is: 153 * $42.84 = $6,554.52.</span>
kirill [66]3 years ago
5 0

Answer:

D is the answer

Step-by-step explanation:


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<em>Greetings from Brasil...</em>

In function F(X) = X², if we replace X with X + 4 we will have exactly function G(X) = (X + 4)²

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F(X + 4) ⇔ F(X + k)  <em>  see below</em>

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A theory predicts that the mean age of stars within a particular type of star cluster is 3.3 billion years, with a standard devi
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Answer:

Null hypothesis:\mu \leq 3.3  

Alternative hypothesis:\mu > 3.3  

z=\frac{3.4-3.3}{\frac{0.4}{\sqrt{50}}}=1.768  

Since is a one right tailed test the p value would be:  

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Step-by-step explanation:

Data given and notation

\bar X=3.4 represent the sample mean  

\sigma=0.4 represent the population deviation for the sample

n=50 sample size  

\mu_o =3.3 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 3.3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.3  

Alternative hypothesis:\mu > 3.3  

Compute the test statistic  

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

z=\frac{3.4-3.3}{\frac{0.4}{\sqrt{50}}}=1.768  

P value

Since is a one right tailed test the p value would be:  

p_v =P(z>1.768)=0.039  

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