This is true.................
Answer:
ρ = 830.32 kg/m³
Explanation:
Given that
Oil head = 12.2 m
h= 12.2 m
Pressure P = 1.013 x 10⁵ Pa
Lets take density of the liquid =ρ
The pressure due to liquid P given as
P = ρ g h
Now by putting the all values in the above equation
1.013 x 10⁵ Pa = ρ x 10 x 12.2 ( take g =10 m/s²)
ρ = 830.32 kg/m³
Therefore the density of oil is 830.32 kg/m³
Answer:
Acceleration:
C. Meters per second squared
Velocity:
B. Meters per second
Distance:
A. Meters
Explanation:
We must remember that the international system of measures (SI) takes into account for the length as the main unit the meter, for the mass the kilogram, for the time the second.
The acceleration is calculated using the following expression
a = v/t = (m/s/s) = (m/s^2]
The velocity is calculated using the following expression
v = x/t = (m)/(s) = (m/s)
The distance for the SI system is given in meters
Answer: 2.5N
Explanation:
Given the following :
Mass of block (m) = 2kg
Coefficient of static friction (μs) = 0.4
Horizontal force applied to the block = 2.5N
The frictional force (Ff) between the block and the floor is :
First calculate the maximum static frictional force:
Frictional force = Coefficient of static friction(μs) × normal reaction(R)
Normal reaction(R) = mass × acceleration due to gravity (10m/s^2)
R = 2 × 10 = 20
Fmax = μs × R
Fmax = 0.4 x 20 = 8N
Here, since the applied force (2.5N) is less than maximum frictional force(8N).
The force of friction between the block and the floor will be equal to the applied force of 2.5N due its ability to adjust itself in other to ensure equilibrium.
The problem is a free fall problem as the camera drops. The vertical velocity is zero. It is the action of gravity that takes place here. To calculate the time it takes to reach the ground, we do as follows:
t = √2y/g = √(2)(70)/9.81 = 3.78 s
The velocity as it impacts the ground would be,
v = √2gy = 37.04 m/s
Hope this helps.