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3 years ago

A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration?

Physics

1 answer:

mixer [17]3 years ago

3 0

Answer:

We are Given:

initial velocity (u) = 0m/s

final velocity (v) = 25 m/s

time (t) = 10 seconds

acceleration (a) = a m/s/s

From the first equation of motion, we know that:

v = u + at

solving for a, we get:

a = (v-u) / t

now, plugging the given values in this equation

a = (25 - 0) / 10

a = 25 / 10

a = 2.5 m/s/s

Therefore, the acceleration of the car is 2.5 m/s/s

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Answer:

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$C = \frac{Q}{V} = \epsilon_0\frac{A}{d}$

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In order to halve the charge stored the plate separation should be half the original distance.

d) Same question as (c).

e) The energy stored in a capacitor is

$U = \frac{1}{2}CV^2 = \frac{1}{2}\epsilon_0\frac{A}{d}(Ed)^2 = \frac{1}{2}\epsilon_0AE^2d$

In order to halve the energy stored in the capacitor, the plate separation should be twice the original distance.

f) Same question as (e).

g) The energy density is given by the following equation

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3 years ago

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3 years ago

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Answer:

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