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Maurinko [17]
3 years ago
7

A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration?

Physics
1 answer:
mixer [17]3 years ago
3 0

Answer:

We are Given:

initial velocity (u) = 0m/s

final velocity (v) = 25 m/s

time (t) = 10 seconds

acceleration (a)  = a m/s/s

From the first equation of motion, we know that:

v = u + at

solving for a, we get:

a = (v-u) / t

now, plugging the given values in this equation

a = (25 - 0) / 10

a = 25 / 10

a = 2.5 m/s/s

Therefore, the acceleration of the car is 2.5 m/s/s

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adell [148]

Answer:

19.3

Explanation:

Assuming we have to find Specific gravity of gold.

As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object

so it is given by

specific gravity = weight of the object/weight of the water displaced

now we have

weight of the object = (density)(volume)g

weight of object = (19.3)(0.55)g

now weight of the liquid displaced is given by

weight of water displaced = (1 g/cm^3)(0.55ml)g

now we have

specific gravity = (19.3×0.55)/(1×0.55)

specific gravity= 19.3

8 0
3 years ago
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sineoko [7]

Answer:

b)

Explanation:

If the charge is released at rest in an electric field, it will move along the electric field, going to regions of higher electric potential if it is a negative charge (against the field direction) and towards lower potential regions if it is positive (along the field). This means that the charge will gain kinetic energy, energy that only can come from a decrease in the electric potential energy.

For a positive charge: ΔEp = q*ΔV < 0 (as ΔV < 0)

For a negative charge: ΔEp = (-q) *ΔV < 0 (as ΔV > 0)

4 0
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Those are all "acceleration", caused by
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3 years ago
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An electric filament lamp is connected to a power supply and switched on.
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