Question

I need help, please help an object starts from rest at time t=0 and moves in the x direction with constant acceleration. The object travels 12m from time t=1 to time t=2. what is the acceleration of the object?

Answer 1

Since the object starts from rest, you can express it's initial velocity in the
period between t=1 and t=2 in terms of the acceleration:v(t)=v0+a∗Δt

v(1)=0+a∗1=a

and substitute this result to the x(t) position equation:

x(Δt)=v0∗Δt+0.5∗a∗Δt2

x(1−>2)=a∗1+0.5∗a∗1=1.5∗a=12

and from here you get:

a=8(m/sec2)