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pickupchik [31]
3 years ago
13

A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has

a period of 0.5 seconds. Determine the length of the rope (the radius of the circle. ​
Physics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

<u>r = 0.5 m</u>

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Explanation:

It is given that,

Diameter of the peach pie, d = 9 inches

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The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches

Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

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Since, 1 radian = 57.29 degrees

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Answer:

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Explanation:

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ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

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