Answer:
B) 71.5 [km]
Explanation:
To solve this problem we will decompose each of the directions in the x & y axes.
To solve this problem we will decompose each of the directions in the x & y axes. also for a greater understanding of the angles, you should look at the attached image, which contains the orientations for each angle (clockwise or counterclockwise).
<u>59.0 km in a direction 30.0° east of north</u>
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![d_{1x}= 59*sin(30) = 29.5[km]\\d_{1y}= 59*cos(30) = 51.09[km]](https://tex.z-dn.net/?f=d_%7B1x%7D%3D%2059%2Asin%2830%29%20%3D%2029.5%5Bkm%5D%5C%5Cd_%7B1y%7D%3D%2059%2Acos%2830%29%20%3D%2051.09%5Bkm%5D)
<u>58.0 km due south</u>
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![d_{2y} = - 58 [km]\\](https://tex.z-dn.net/?f=d_%7B2y%7D%20%3D%20-%2058%20%5Bkm%5D%5C%5C)
<u>It flies 100 km 30.0° north of west</u>
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Now we sum algebraically the components
![d_{x}=29.5-86.6 = -57.1[km]\\d_{y}=51.09 -58+50=43.09[km]\\\\](https://tex.z-dn.net/?f=d_%7Bx%7D%3D29.5-86.6%20%3D%20-57.1%5Bkm%5D%5C%5Cd_%7By%7D%3D51.09%20-58%2B50%3D43.09%5Bkm%5D%5C%5C%5C%5C)
Using the Pythagorean theorem we can find the magnitude of the displacement.
![d = \sqrt{(57.1)^{2} +(43.09)^{2} } \\d= 71.53[km]](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%2857.1%29%5E%7B2%7D%20%2B%2843.09%29%5E%7B2%7D%20%7D%20%5C%5Cd%3D%2071.53%5Bkm%5D)
April 8, 2024
Eclipse will be total over the southern part of the state. Roughly everything south of Decatur and Springfield.
The ball was moving for 0.8seconds
This is because 4/5 x 1 = 0.8
Hope this helps and good luckkkk :)
<u>Answer:</u>
First, the thermometer is dipped into boiling water, and the mercury inside the thermometer rises to a high level, called the boiling point. This level is then marked as 100°C. The thermometer is then dipped into melting ice, which causes the mercury level to fall to a point called the ice point. This point is then marked as 0°C. The length of the thermometer from the 0°C mark to the 100°C point is then divided into 100 equal sections, and the rest of the levels are marked accordingly.