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jarptica [38.1K]
4 years ago
10

No point source comes from a variety of locations and is easy to trace

Physics
2 answers:
Inessa05 [86]4 years ago
6 0
Nonpoint source comes from a Specific locations and is easy to trace.

So it's false.
sergejj [24]4 years ago
3 0
Nonpoint* source pollution does come from a variety of locations, but it is NOT easy to trace. This statement is false.
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A car staring from rest accelerates at 12 m/s^2, what distance did it travel in 7 seconds? (Show work)
Sati [7]
X = v0+ 1/2 a t^2
X= 0+1/2(12 m/s^2 ) ( 7 s)^ 2
X= 6 m/s^2 ( 49 s^2)
X= 294 m
8 0
3 years ago
A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill
ozzi

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

4 0
3 years ago
How long does GSR last ?
SSSSS [86.1K]

Answer:

i think that the answer might be be C. one day. because it last about 4 to 6 hours

4 0
3 years ago
...............................................................help
chubhunter [2.5K]

Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²

hmax = 11481.77m - 5741.29m

hmax = 5740.48m

3 0
3 years ago
The amount of straight pipe needed to bend a given radius. Also, the actual length of the conduit that will be bent.
slava [35]

Development length: The actual length of the bent conduit. Gain: Since a conduit bends radially rather than at an angle, the total length will not match the length required for all bends. Gain is the amount of space that is saved by a 90^{0} curve.

<h3>Bent Conduit</h3>

Conduit benders from Klein Tools are built to function and last longer than even the highest professional standards. To ensure a favourable experience and significantly enhance the final result of your project, it is advised that you become familiar with bending concepts, procedures, and the bender's capabilities. The benders are labelled with various alignment symbols to enable the operator make the bends required to complete any job. This aids bending while executing a ground or air bend. Arrow, teardrop, star point, and angle markings are the symbols on the Klein Tools benders. On certain bender head sides, you can see these markings.

Learn more about bent conduit here:

brainly.com/question/5023977

#SPJ4

8 0
2 years ago
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