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qwelly [4]
3 years ago
12

A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill

Physics
1 answer:
ozzi3 years ago
4 0

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

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Answer:

<u>400</u> J work is done BY the engine.

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Explanation:

The given information are;

The heat added to the cylinder = 620 J

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The distance over which the force moves (the piston) = 5.0 cm = 0.05 m

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The internal energy is the sum of the kinetic and potential energy of the system

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6 0
2 years ago
Suppose a firm is producing 2,475 units of output by hiring 50 workers (W = $20 per hour) and 25 units of capital (R = $10 per h
Neko [114]

Answer

given,

firm is producing  = 2,475 units

output by hiring 50 workers W = $20 per hour

25 units of capital R = $10 per hour

marginal product of labor = 40

marginal product of capital = 25

\dfrac{MP_l}{MP_c}=\dfrac{40}{25}

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Firm is not minimizing the cost because the firm use more capital and less labor.

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guapka [62]
Then, number of protons would be equal to number of electrons.
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Answer:

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