Answer:
(a) 8.117 (b) 0.742
Explanation:
We have given distance s =40 m time t=7.5 sec
Final velocity v =2.55 m/sec
From the first equation of motion
(negative sign because there is retrdation as the truck speed is slowing down )
So
--------------eqn 1
From the second equation of motion
( negative sign because there is retrdation as the truck speed is slowing down )
So 
------------------eqn 2
On solving eqn1 and eqn 2
u=8.117 m/sec and a=-0.742
To determine the height of the object given the time, we simply use the given relation between height and time in the problem statement. It is given as:
h = -16t^2 + 127t
We substitute 55 seconds to t and obtain,
h = -16(55)^2 + 127(55)
h = - 41415
Because of how it's worded the answer would most likely be number four