The amount of straight pipe needed to bend a given radius. Also, the actual length of the conduit that will be bent.

1 answer:

8 0

Development length: The actual length of the bent conduit. Gain: Since a conduit bends radially rather than at an angle, the total length will not match the length required for all bends. Gain is the amount of space that is saved by a $90^{0}$ curve.

<h3>Bent Conduit</h3>

Conduit benders from Klein Tools are built to function and last longer than even the highest professional standards. To ensure a favourable experience and significantly enhance the final result of your project, it is advised that you become familiar with bending concepts, procedures, and the bender's capabilities. The benders are labelled with various alignment symbols to enable the operator make the bends required to complete any job. This aids bending while executing a ground or air bend. Arrow, teardrop, star point, and angle markings are the symbols on the Klein Tools benders. On certain bender head sides, you can see these markings.

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Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

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Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

$T^2 \propto R^3$

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

$T^2 \propto R^3$

$T^2 = kR^3$

Substituting the values, we get the value of constant k for mars.

$687^2 = k\times (2.279 \times 10^{11})^3$

$k = 3.92 \times 10^{-29}$

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

$365^3 = 3.92\times 10^{-29} R^3$