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likoan [24]
3 years ago
7

What we call the state in a human body if cerebrum is not functioning well​

Physics
1 answer:
Y_Kistochka [10]3 years ago
5 0
Depending on the area and side of the cerebrum affected, any, or all, of these functions may be impaired: Movement and sensation; speech and language; eating and swallowing.
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A 40 kg girl and an 8.4 kg sled are on the surface of a frozen lake, 15 m apart. By means of a rope, the girl exerts a 5.2 N for
stealth61 [152]

Answer:

(a) a_s=0.62\frac{m}{s^2}

(b) a_s=0.13\frac{m}{s^2}

(c) x_f=2.6m

Explanation:

(a) According to Newton's second law, the acceleration of a body is directly proportional to the force exerted on it and inversely proportional to it's mass.

a_s=\frac{F}{m_s}\\a_s=\frac{5.2N}{8.4kg}\\a_s=0.62\frac{m}{s^2}

(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:

a_g=\frac{F}{m_g}\\a_g=\frac{5.2N}{40kg}\\a_g=0.13\frac{m}{s^2}

(c) Using the kinematics equation:

x_f=x_0+v_0t \pm  \frac{at^2}{2}

For the girl, we have x_0=0 and v_0=0. So:

x_f_g=\frac{a_gt^2}{2}(1)

For the sled, we have v_0=0. So:

x_f_s=x_0_s-\frac{a_st^2}{2}(2)

When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:

x_0_s-\frac{a_st^2}{2}=\frac{a_st^2}{2}\\t^2(a_g+a_s)=2x_0_s\\t=\sqrt{\frac{2x_s_0}{a_g+a_s}}\\t=\sqrt{\frac{2(15m)}{0.13\frac{m}{s^2}+0.62\frac{m}{s^2}}}\\t=6.32s

Now, we solve (1) for x_f_g

x_f_g=\frac{0.13\frac{m}{s^2}(6.32s)^2}{2}\\x_f_g=2.6m\\x_f=2.6m

5 0
3 years ago
Please someone derive 3rd equation of motion u- v= 2sa​
zlopas [31]

We know

\\ \sf\longmapsto a=\dfrac{dv}{dt}

\\ \sf\longmapsto a=\dfrac{dv}{dx}.\dfrac{dx}{dt}

\\ \sf\longmapsto a=v\dfrac{dv}{dx}

\\ \sf\longmapsto adx=vdv

  • Integrate

\\ \sf\longmapsto a{\displaystyle{\int}^x_{x_0}}dx=\displaystyle{\int}_u^v vdv

\\ \sf\longmapsto a(x-x_0)=\dfrac{v^2-u^2}{2}

Here

  • x-x_0=s

\\ \sf\longmapsto v^2-u^2=2as

6 0
3 years ago
Read 2 more answers
Which describes the movement of a fluid during convection?
VikaD [51]
The movement of a fluid during convection is a circular/oval motion since the fluid at the top sinks and the fluid at the bottom rises.

Hope this helps :)
3 0
4 years ago
A hollow plastic sphere is held below the surface of a fresh-water lake by a cord anchored to the bottom of the lake. The sphere
Naya [18.7K]

Answer: a) B = 6811N

              b) m = 603.2kg

              c) 86.8%

Explanation: <em>Buoyant force</em> is a force a fluid exerts on a submerged object.

It can be calculated as:

B=\rho_{fluid}.V_{obj}.g

where:

\rho_{fluid} is density of the fluid the object is in;

V_{obj} is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

B=10^{3}.0.695.9.8

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are <u>Buoyant</u>, <u>Tension</u> and <u>Force due to gravity</u>:

B = T + F_{g}

B = T + mg

mg = B - T

m=\frac{B - T}{g}

Calculating:

m=\frac{6811 - 900}{9.8}

m = 603.2kg

c) When the shpere comes to rest on the surface of the water, there are only <u>buoyant</u> <u>and</u> <u>gravity</u> acting on it:

B = m.g

\rho_{w}.V_{sub}.g=m.g

V_{sub}=\frac{m}{\rho_{w}}

V_{sub}=\frac{603.2}{1000}

V_{sub} = 0.6032m³

Fraction of the submerged volume is:

\frac{V_{sub}}{V_{obj}} = \frac{0.6932}{0.695} = 0.868

<u />

3 0
3 years ago
A car has a weight of 25000 N and its brakes can apply a maximum force of 628 N to stop it. The car is initially moving at a spe
svlad2 [7]

Time required : 25.876 s

<h3>Further explanation</h3>

Given

A car weight = 25000 N

Brake force = 628 N

vo= 6.5 m/s

vt = 0(stop)

Required

time to stop

Solution

W = m . g

25000 = m.10

m=2500 kg

Newton's second law

F = m . a

628 = 2500 . a

\tt a=\dfrac{628}{2500}=0.2512~m/s^2

vt=vo-at(deceleration a=-)

0=6.5-0.2512.t

0.2512.t=6.5

t=25.876 s

5 0
3 years ago
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