Question

A woman takes her dog Rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the horizontal sidewalk. What force is tending to pull Rover forward, parallel to the horizontal?

Answer 1

Answer:

The force parallel to the horizontal is 26.24 N

Explanation:

She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle $\theta$), it has a force component on x (the horizontal, i will call this force $F_{x}$) and a force component on y (the vertical, i will call this $F_{y}$ ).

This can be seen in the attached picture.

Since we are asked about the force parallel to the horizontal, we need to find the component of the force $F_{x}$, since $F_{x}$ is the adjacent angle, we need to use cosine:

$F_{x}=Fcos \theta$

since $F=30N$ and $\theta=29$

$F_{x}=(30N)cos(29)$

$F_{x}=(30N)(0.8746)$

$F_{x}=26.24N$

The force parallel to the horizontal is 26.24 N