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Gemiola [76]
3 years ago
9

A woman takes her dog Rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the ho

rizontal sidewalk. What force is tending to pull Rover forward, parallel to the horizontal?

Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

The force parallel to the horizontal is 26.24 N

Explanation:

She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle \theta), it has a force component on x (the horizontal, i will call this force F_{x}) and a force component on y (the vertical, i will call this F_{y} ).

This can be seen in the attached picture.

Since we are asked about the force parallel to the horizontal, we need to find the component of the force F_{x}, since F_{x} is the adjacent angle, we need to use cosine:

F_{x}=Fcos \theta

since F=30N and \theta=29

F_{x}=(30N)cos(29)

F_{x}=(30N)(0.8746)

F_{x}=26.24N

The force parallel to the horizontal is 26.24 N

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Answer:

θ = 36.2º

Explanation:

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Explanation:

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And that is the kinetic energy that the dog needs.
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