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brilliants [131]

3 years ago

13

A very large magnet applies a repulsive force to a smaller (0.05 Kg) magnet. If the smaller magnet accelerates across a friction

less table at 2m/s2, then what is the magnitude of the repulsive force?

1 answer:

makkiz [27]3 years ago

5 0

Answer:

0.1 N

Explanation:

using F = ma yields 0.1 N.

net

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A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I

scZoUnD [109]

Answer:

Magnification will be equal to 3

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We have given focal length of the converging lens $F_1=20cm$

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Combination of the focal length will be equal to

$\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}$

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