3x + 5y = 7 4x + 3y = 2 Both x and y have to be the same numbers!
2 answers:
Simultaneous Equations:
(3x + 5y = 7)×(-3)
(4x + 3y = 2)×(5)
-9x - 15y = -21
20x+15y =10 (-15y and and+15y cancels out)
11x = -11
= 
(11 and 11 cancels out)
x= -1
substitute the x we found into either original expressions
3(-1) + 5y = 7
-3 + 5y = 7
+3 -3+ 5y = 7+ 3
5y = 10
=
(5 and 5 cancels out)
y=2
Check it!
4(-1)+3(2) = 2
-4 + 6 = 2
2 = 2
3(-1) + 5(2) = 7
-3 + 10 = 7
7 = 7
x= -1
y= 2
(3x + 5y = 7)×(-3)
(4x + 3y = 2)×(5)
-9x - 15y = -21
20x+15y =10 (-15y and and+15y cancels out)
11x = -11
x= -1
substitute the x we found into either original expressions
3(-1) + 5y = 7
-3 + 5y = 7
+3 -3+ 5y = 7+ 3
5y = 10
y=2
Check it!
4(-1)+3(2) = 2
-4 + 6 = 2
2 = 2
3(-1) + 5(2) = 7
-3 + 10 = 7
7 = 7
x= -1
y= 2
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Answer:
The correct option is 4.
Step-by-step explanation:
The non parallel sides of an isosceles trapezoid are congruent.
The image of an isosceles trapezoid is same as the preimage of isosceles trapezoid if
1. Reflection across a line joining the midpoints of parallel sides.
2. Rotation by 360° about its center.
3. Rotation by 360° about origin.
If we rotate the trapezoid by 180° about its center, then the parallel sides will interchanged.
If we reflect the trapezoid across a diagonal, then the resultant figure will be a parallelogram.
If we reflect across a line joining the midpoints of the nonparallel sides, then the parallel sides will interchanged.
After rotation by 360° about the center, we always get an onto figure.
Therefore option 4 is correct.
