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3 years ago

IT WUU Tate for school on a

Mathematics

1 answer:

Blizzard [7]3 years ago

3 0

Answer:

Number of students = 441 Students

Step-by-step explanation:

Given:

Percent of women = 40%

Percent of women = 35.5%

Total number of people = 1,800

Find:

Number of students

Computation:

Percent of student = 100% - 35.5% - 40%

Percent of student = 24.5%

Number of students = 1,800 x Percent of student

Number of students = 1,800 x 24.5%

Number of students = 441 Students

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Which point satisfies the system of equations y= 3x - 2 and y=-2x + 3?

monitta

Answer:

The points which satisfy the given lines is ( 1 , 1 )

Step-by-step explanation:

Given as :

The equation of lines is

y = 3 x - 2 ........ 1 And

y = - 2 x + 3 ........ 2

From equation given

3 x - 2 = - 2 x + 3

Or , 3 x + 2 x = 3 +2

Or, 5 x = 5

So , x = $\frac{5}{5}$ = 1

Put the value of x in eq 1

So, y = 3 ( 1 ) - 2

Or, y = 3 - 2 = 1

∴, the points ( x , y ) = ( 1 , 1 )

Hence The points which satisfy the given lines is ( 1 , 1 ) Answer

5 0

3 years ago

Please help me guys with this problem.

Anna71 [15]

I think the answer is 152 but I’m not 100% sure

7 0

3 years ago

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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

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3 years ago

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VladimirAG [237]

1. A in some part is correct, but the triangles are indeed correct, and the argument is for HL, so the answer is C

2. Are congruent by SSS (both shares a side).

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3 years ago

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I need question 3 only

dsp73

Answer:

table: 14, 16, 18
equation: P = 2n +12

Step-by-step explanation:

Perimeter values will be ...

rectangles . . . perimeter

1 . . . 14

2 . . . 16

3 . . . 18

The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...

P = 2(6 +n) = 12 +2n

Your equation is ...

P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.

_____

<em>Additional comment</em>

You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...

y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles

4 0

3 years ago