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netineya [11]
4 years ago
5

Which of the following is a pattern of biogeography that supports the theory of evolution? A. Closely related organisms that liv

e in different environments are often very different from each other. B. Analogous structures show common descent for unrelated species. C. Closely related organisms that live in different environments don't show any different adaptations. D. Analogous structures show that living in similar habitats doesn't lead to similar adaptations.
Biology
1 answer:
12345 [234]4 years ago
6 0

I believe <u>B.) Analogous structures show that living in similar habitats doesn't lead to similar adaptations </u>is your right answer.

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Biodiversity

Explanation:

They will of course exhibit the biodiversity of that given habitat because diversity refers to variation in abroad terms and can be applied to any area.

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What can happen to the soil after the mice have destroyed the roots of the grass?
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3 years ago
A water sample has a pH 10 and contains 56 mg/L HCO3- and 32 mg/L CO32-. Calculate the alkalinity in mg/L as CaCO3.
Greeley [361]

The alkalinity as CaCO3 in mg/L is 108,23

<h3>What is alkalinity?</h3>

Alkalinity is the total measure of substances present in water, capable of neutralizing acids. In other words, it is the amount of substances present in the water that act as a buffer.

With that being said;

Equivalent weight = {molar mass}*{ion charge/oxidation number}

  • Molar mass of HCO3- = 61g/mol
  • Molar mass of CO3 = 60g/mol
  • Molar mass of CaCO3 = 100g/mol

  • Eq. cot. of HCO3- = 61g/Eq
  • Eq. cot. of CO3 = 30g/Eq
  • Eq. cot. of CaCO3 = 50g/Eq

Alkalinity due to CO3 = {32x50}{30} = 53.33mg/L

Alkalinity due to HCO3- = {56x50}{61} = 54,90mg/L

Total Alkalinity = 53,33 + 54,90 = 108,23 mg/L

In this case, we have to The alkalinity as CaCO3 in mg/L is 108,23 mg/L

See more about pH at: brainly.com/question/15289741

#SPJ1

5 0
2 years ago
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