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spin [16.1K]
3 years ago
13

1. I have a concentration of 300g of sugar for every 100 mL of water. What is the lowest possible temperature I would need to di

ssolve that much sugar? ____________.

Chemistry
1 answer:
Dimas [21]3 years ago
7 0

Answer:

64 °C

Explanation:

I’m guessing that “they” are asking you to interpret a solubility curve something like the one below.

Find the point at 300 g/100 mL water on the vertical axis.

From there, draw a horizontal line until it meets the solubility curve of sugar.

Then, drop a vertical line to the temperature axis.

It appears to hit the axis at about <em>64 °C</em>.

The solution is saturated at this temperature, so 64 °C is the lowest temperature at which you can dissolve 300 g of sugar in 100 mL of water.

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Pyruvate dehydrogenase is a large, highly integrated complex containing many copies of three distinct enzymes. There are five co
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Answer:

The correct answer is a  coenzyme cosubstrate is loosely bound to an enzyme and dissociates in an altered form as the part of the catalytic cycle.Its original form is regenerated not by the cycle but by other enzyme.

Explanation:

The  prosthetic group of the enzyme pyruvate dehydrogenase is

2 TPP or Thymine pyrophosphate.

3  Lipomide.

6 0
4 years ago
Which diagram represents an object at static equilibrium?
Marianna [84]
The absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.
4 0
3 years ago
Read 2 more answers
Someone please help me??
Scrat [10]
The answer is 0.18

Because the equation for finding the molarity of a solution is:

Moles divided by Liter of solution,

so, you dissolve 0.32 mol of KCL in 1759 ml of Water 1759 ml is 1.759 liters when you plug the numbers in you get 0.18

Hope this helps, 

kwrob
6 0
3 years ago
What is the difference between gases and nonmetal?
ExtremeBDS [4]

Answer:

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3 0
3 years ago
Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
3 years ago
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