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77julia77 [94]
3 years ago
6

Hdhdhzjzjzj which??????????????????

Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

I think it’s D but not sure

Explanation:

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A mixture of 50.0 mL of ammonia gas and 60.0 mL of oxygen gas react. If all the gases are at the same temperature and pressure,
fredd [130]

Answer:

72.0 mL of steam is formed.

Explanation:

The reaction is :

4 NH_{3} + 5O_{2} \rightarrow 4NO+6H_{2} O

You can treat coefficient of compounds as amount of volume used.

Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.

For 1 mL of ammonia \frac{5}{4} (=1.25) mL of oxygen is used to form \frac{4}{4} (=1) mL of nitric oxide gas and \frac{6}{4} (=1.5) mL of steam.

OR

Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of NH_{3} become one like this

NH_{3} + \frac{5}{4} O_{2} \rightarrow \frac{4}{4}NO+\frac{6}{4}H_{2} O

We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :

<em>1.  </em><em>Assume ammonia to be completely exhausted</em>

For 50 mL of ammonia 50 \times \frac{5}{4} (= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.

2.  <em>Assume oxygen to be completely exhausted</em>

For 60 mL of oxygen only 60 \times \frac{4}{5} (=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.

60\times\frac{4}{5}NH_{3} + 60\ O_{2} \rightarrow 60\times\frac{4}{5}NO+60\times\frac{6}{5}H_{2} O\\\\48NH_{3} + 60\ O_{2} \rightarrow 48NO+72H_{2} O

Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form 60 \times \frac{4}{5} (= 48) mL of nitic oxide gas and 60 \times \frac{6}{5} (= 72) mL of steam.

Therefore <em>72 mL of steam </em>is formed.

5 0
3 years ago
Read 2 more answers
How many moles are in 2.1 x 10^{24} molecules SiO4
lozanna [386]

Answer: 3.5 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of SiO4 = 6.02 x 10^23 molecules

Zmoles of SiO4 = 2.1 x 10^{24} molecules

To get the value of Z, cross multiply:

(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)

Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)

Z = 3.5 moles

Thus, there are 3.5 moles of SiO4.

4 0
3 years ago
wich answer choice contains organisms that are all prokaryotic. A. archaebacteria and bacteria B. bacteria and fungi C. protists
JulijaS [17]

Answer:

Explanation:

no

6 0
3 years ago
If 0.138g of cyclohexene (c6h10) was obtained from 0.240g of cyclohexanol (c6h120), what is the percentage yield of cyclohexene?
tino4ka555 [31]
<span>Given in the question- 1 mole of cyclohexanol = > 1 mole of cyclohexene Molar mass 100.16 g/mol moles of cyclohexanol = .240 / 100.16= 0.002396 moles Molar mass 82.143 g/mol moles of cyclohexene formed @100 % yield = 0.002396 Molar mass 82.143 g/mol mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g bur we have .138g so % yield = .138 / .197 = 70.0 % Ans- 70 percentage yield of cyclohexene.</span>
4 0
3 years ago
A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8
aivan3 [116]

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = n_1=9.79 mol

Initial volume of freon gas in ballon = V_1=?

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol

Final volume of freon gas in ballon = V_2=21.8 L

Using Avogadro's law:

\frac{V_1}{n_1}=\frac{V_2}{n_2} ( at constant pressure and temperature)

V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L

16.06 L was the initial volume of the balloon.

4 0
3 years ago
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