Answer:
72.0 mL of steam is formed.
Explanation:
The reaction is :

You can treat coefficient of compounds as amount of volume used.
Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.
For 1 mL of ammonia
(=1.25) mL of oxygen is used to form
(=1) mL of nitric oxide gas and
(=1.5) mL of steam.
OR
Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of
become one like this

We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :
<em>1. </em><em>Assume ammonia to be completely exhausted</em>
For 50 mL of ammonia
(= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.
2. <em>Assume oxygen to be completely exhausted</em>
For 60 mL of oxygen only
(=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.

Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form
(= 48) mL of nitic oxide gas and
(= 72) mL of steam.
Therefore <em>72 mL of steam </em>is formed.
Answer: 3.5 moles
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 molecules
So, 1 mole of SiO4 = 6.02 x 10^23 molecules
Zmoles of SiO4 = 2.1 x 10^{24} molecules
To get the value of Z, cross multiply:
(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)
2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)
Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)
Z = 3.5 moles
Thus, there are 3.5 moles of SiO4.
<span>Given in the question-
1 mole of cyclohexanol = > 1 mole of cyclohexene
Molar mass 100.16 g/mol
moles of cyclohexanol = .240 / 100.16= 0.002396 moles
Molar mass 82.143 g/mol
moles of cyclohexene formed @100 % yield = 0.002396
Molar mass 82.143 g/mol
mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g
bur we have .138g
so % yield = .138 / .197 = 70.0 %
Ans- 70 percentage yield of cyclohexene.</span>
Answer:
16.06 L was the initial volume of the balloon.
Explanation:
Initial moles of freon in ballon = 
Initial volume of freon gas in ballon = 
Moles of freon gas added in the balloon = n = 3.50 mole
Final moles of freon in ballon = 
Final volume of freon gas in ballon = 
Using Avogadro's law:
( at constant pressure and temperature)

16.06 L was the initial volume of the balloon.