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mrs_skeptik [129]
3 years ago
7

Whose atomic theory explains how atoms emit (release) and absorb light?

Chemistry
2 answers:
inn [45]3 years ago
4 0

Answer:

Bohr's model of hydrogen atom

I hope this answer is correct

IgorLugansk [536]3 years ago
4 0

Answer:

Bohr's

Explanation:

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A sample of paraffin wax undergoes the following change: C25H52(s) → C25H52(l)
nalin [4]

Answer:

Explanation:

(a) Answer: Intermolecular forces

The reason for this answer is because the substance (paraffin wax) only changed it's state from solid to liquid and didn't undergo a breakage in it's covalent bond within it's carbon chain which would have produced another substance.

(b) Solid substances are generally more dense than there corresponding liquid substances because the more compact particles are (which occurs in solids), the more dense they become. They are thus more dense than liquids because liquids have there particles loosely packed and well spaced making them less dense than there corresponding solids. Hence, the solid paraffin wax was going to become less dense because it's particles moved from being tightly packed (as solids) to being loosely packed (as liquids). Density refers to mass per volume but can also be described as the level of compactness of a substance. Thus, since liquid is not as compact as solid, it can be said to be less dense than solids.

5 0
3 years ago
A scientist would most likely need to update her model when it
Marizza181 [45]
A scientist would most likely need to update her model when it no longer supports the latest results.
5 0
3 years ago
Read 2 more answers
Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization e
Effectus [21]

Let us check each statement one by one

a) Sb has a lower ionization energy but a higher electronegativity than I. : As per values given : Definitely Sb has lower ionization energy however the electronegativity of Sb is lower than that of iodine

b) Sb has a higher ionization energy but a lower electronegativity than I. FAlse:

Sb has lower ionization energy than I

c) Sb has a lower ionization energy and a lower electronegativity than I. True

d) Sb has a higher ionization energy and a higher electronegativity than I. False


4 0
4 years ago
Read 2 more answers
One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic transition that begins in the state w
4vir4ik [10]

Answer:

4

Explanation:

Relationship between wavenumber and Rydberg constant (R) is as follows:

wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}

Here, Z is atomic number.

R=109677 cm^-1

Wavenumber is related with wavelength as follows:

wavenumber = 1/wavelength

wavelength = 253.4 nm

wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}

Z fro Be = 4

39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4

Therefore, the principal quantum number corresponding to the given emission is 4.

6 0
4 years ago
When butter is heated it melts and when that melted butter cools and solidifies the process called
avanturin [10]
<span>I'm pretty sure it is called condensation</span>
3 0
3 years ago
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