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docker41 [41]
3 years ago
12

Mary, the mouse, was hiding in the rocks when she saw a sandwich hit the ground at

Chemistry
1 answer:
Georgia [21]3 years ago
8 0
4.5seconds of spead yw
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Examine the structure of glucose and galactose which oh group determines that they both are the d isomers
garri49 [273]

Answer:

See Explanation

Explanation:

Stereoisomers are isomers that have the same atom to atom connectivity but differ in the arrangement of atoms or groups in space.

Glucose and galactose are stereoisomers that have more than one stereogenic center but differ in the configuration of atoms and groups about one of the stereogenic centers. This kind of stereoisomers are also called epimers.

Glucose and galactose differ in the orientation of -H and -OH at carbon-4.

6 0
3 years ago
Which of the following are hydrocarbons?
Elden [556K]

Answer:

B or C

Explanation:

I think it's C

8 0
2 years ago
A mole is equal to 6.02 x 10²³, just like a dozen is equal to 12. So if you have a mole of carbon atoms, you have 6.02 x 10²³ ca
Lyrx [107]
You must perform stoichiometry! always divide by what you already have (this will make since in a moment)

5.2g Carbon | 1 mole/12.01g/mole | 6.02 x 10^23 atoms/1 mole | = atoms in Carbon

above is the basic stoichiometry set up but your calculation should be (5.2g/12.01g) x (6.02 x 10^23) = 2.61 x 10^23 atoms
6 0
4 years ago
Perform the following conversions:
jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=\frac{5}{9}\times (^oF-32)

The conversion used for the temperature from degree Celsius to Kelvin is:

K=^oC+273

(a) 1.06^oF

^oC=\frac{5}{9}\times (^oF-32)

^oC=\frac{5}{9}\times (1.06^oF-32)

^oC=-17.188

The temperature in degree Celsius is, -17.188^oC

K=^oC+273

K=-17.188+273

K=255.812

The temperature in Kelvin is, 255.812 K

(b) 3410^oC

^oC=\frac{5}{9}\times (^oF-32)

3410^oC=\frac{5}{9}\times (^oF-32)

^oF=6106

The temperature in degree Fahrenheit is, 6106^oF

K=^oC+273

K=3410+273

K=3683

The temperature in Kelvin is, 3683 K

(c) 6.1\times 10^3K

K=^oC+273

6.1\times 10^3K=^oC+273

^oC=5827

The temperature in degree Celsius is, 5827^oC

^oC=\frac{5}{9}\times (^oF-32)

5827^oC=\frac{5}{9}\times (^oF-32)

^oF=10456.6

The temperature in degree Fahrenheit is, 10456.6^oF

8 0
3 years ago
When was tin discovered tin is an element please help 75 pts
torisob [31]
 It was used from the Bronze Age(3000 BC) and tin was used in the bronze. 
8 0
4 years ago
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