The work done is 315 J
Explanation:
The graph is missing: find it in attachment.
The work done by a variable force is given by
where
F(x) is the magnitude of the force
x is the position
On a force vs position graph, the work done is equivalent to the area under the graph. Therefore, in order to find the work done as the block moves from x = 0 to x = 8.0 m, we have to calculate the area under the graph between these two points.
Each square corresponds (vertically) to 45 N, so the area of the first trapezium between x = 0 and x = 4.0 m is
Then we have to find the area of the triangle between x = 6.0 m and x = 8.0 m:
Therefore, the total area (and the work done) is
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White dwarf is white and dim
Answer:
q₃ = - 13.0935 μC
Explanation:
Given
q₁ = q₂ = +7.67 μC
We use the equation
V = Kq/r
We can apply it as follows
V₁ = K*q₁/r₁ = K*q₁/(√2*L)
V₂ = K*q₂/r₂ = K*q₂/L
V₃ = K*q₃/r₃ = K*q₃/L
Then
V₁ + V₂ + V₃ = 0
⇒ (K*q₁/(√2*L)) + (K*q₂/L) + (K*q₃/L) = 0
⇒ (K/L)*((q₁/√2) + q₂ + q₃) = 0
⇒ (q₁/√2) + q₂ + q₃ = 0
Since q₁ = q₂
⇒ (q₁)((1/√2) + 1) + q₃ = 0
⇒ q₃ = - (q₁)((1/√2) + 1) = +7.67 μC*(1.7071)
⇒ q₃ = - 13.0935 μC
Answer:
400N
Explanation:
If you have 2 forces (200N) and (200N) pushing an object the same direction in a one dimensional force vectors, the answer would be 400N
1000 litres of water can fill a tank of 1m3 capacity because water has a density of 1000kg/m3 and as 1 kg water = 1 liter ,
1000 liter of water can fill a tank of 1m3