Question

Calculate the number of moles of gas present in the sealed container at a

Answer 1

Here volume of gas is not given so question is solved assuming volume as 1 L.

The number of moles of 1 L gas present in the sealed container at a

pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.

The ideal gas law equation can be written as

PV  = nR T

Here

P is the pressure of the gas in atm

V is the volume it occupies in L

n is the number of moles of gas present in the sample

R is the universal gas constant, equal to 0.0821 atm L/ mol K

T is the absolute temperature of the gas in Kelvin

Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.

So

P = 125 kPa

1 atm = 760 kPa

P = 125/760 = 0.1644 atm

T = 25 degree celsius  = 25 +273 = 298 K

Taking V  = 1 L

So

n  = PV/RT

n = 0.1644 x 1 / 0.0821 x 298

n =  0.0067 moles

To learn more about the ideal gas law, please click on the link brainly.com/question/128737528

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