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Akimi4 [234]
3 years ago
14

A 5 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with posit

ion as shown in the figure. The scale of the figure's vertical axis is set by Fs = 45 N. How much work is done by the force as the block moves from the origin to x = 8.0 m?

Physics
1 answer:
jekas [21]3 years ago
5 0

The work done is 315 J

Explanation:

The graph is missing: find it in attachment.

The work done by a variable force is given by

W=\int F(x) dx

where

F(x) is the magnitude of the force

x is the position

On a force vs position graph, the work done is equivalent to the area under the graph. Therefore, in order to find the work done as the block moves from x = 0 to x = 8.0 m, we have to calculate the area under the graph between these two points.

Each square corresponds (vertically) to 45 N, so the area of the first trapezium between x = 0 and x = 4.0 m is

A_1 = \frac{(4+2)\cdot 2\cdot 45)}{2}=270

Then we have to find the area of the triangle between x = 6.0 m and x = 8.0 m:

A_2 = \frac{1}{2}(2)(45)=45

Therefore, the total area (and the work done) is

W=A_1+A_2=270+45=315 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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A newspaper and a metal lunchbox are sitting in sun. Why does metal lunchbox feel hotter to touch than a newspaper?
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Find the Horizontal (x) vector for these forces.
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Answer:

See the explanation below.

Explanation:

The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.

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Determine the amount of work done on an ideal gas as it is heated in an enclosed thermally insulated cylinder topped with a free
sp2606 [1]

Answer:

W = 3/2 n (T₁- T₂)

Explanation:

Let's use the first law of thermodynamics

           ΔE = Q + W

in this case the cylinder is insulated, so there is no heat transfer

           ΔE = W

internal energy can be related to the change in temperature

            ΔE = 3/2 n K ΔT

we substitute

           3/2 n (T₂-T₁) = W

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3 0
3 years ago
49. A block is pushed across a horizontal surface with a
nata0808 [166]

Answer:

(a) 37.5 kg

(b) 4

Explanation:

Force, F = 150 N

kinetic friction coefficient = 0.15

(a) acceleration, a = 2.53 m/s^2

According to the newton's second law

Net force = mass x acceleration

F - friction force = m a

150 - 0.15 x m g = m a

150 = m (2.53 + 0.15 x 9.8)

m = 37.5 kg

(b) As the block moves with the constant speed so the applied force becomes the friction force.

F = \mu m g \\\\150 = \mu\times 37.5\\\\\mu = 4

8 0
3 years ago
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