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ANEK [815]
4 years ago
9

What is The distance traveled by a vehicle in 12 minutes,if it’s speed is 35km/h

Physics
1 answer:
Delvig [45]4 years ago
3 0

Answer: 7 km

Explanation: 12 minutes is 1/5 of an hour. 35/5=7

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A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same direction. What is the largest distance the stu
stepan [7]

Answer:

7.1 m

Explanation:

Given:

Distance traveled by the student in the first attempt = (2.9 \pm 0.1)\ m

Distance traveled by the student in the second attempt = (3.9 \pm 0.2)\ m

So, the maximum distance that the student could travel in this attempt = (2.9+0.1)\ m = 3.0\ m

So, the maximum distance that the student could travel in this attempt = (3.9+0.2)\ m = 4.1\ m

Since the student first moves straight in a particular direction, rests for a while and then moves some distance in the same direction.

So, the largest distance that the student could possibly be from the starting point would be the largest distance of the final position of the student from the starting point.

And this distance is equal to the sum of the maximum distance possible in the first attempt and the second attempt of walking which is 7.1 m.

Hence, the largest distance that the student could possibly be from the starting point is 7.1 m.

5 0
3 years ago
What distance will an object cover in 20 seconds if it is moving at 8 m/s
Nitella [24]

Answer:

160 m

Explanation:

distance covered in 1 s  = 8 m

therefore, distance covered in 20 s = 8 * 20 m = 160 m

4 0
3 years ago
If the strength of the magnetic field at B is 20 units, the strength of the magnetic field at A is _____.
xz_007 [3.2K]
The answer is A = 20 units
8 0
4 years ago
Read 2 more answers
If a melon has a a mass of 1 kg, how much does the melon weigh?
lesya [120]

Answer:

A. 10 N

Explanation:

weight of melon is 1×10=10N..........

6 0
3 years ago
a boy pulls 23 kg box with a 100 N force at 39 above a horizontal surface if the coefficient of kinetic friciton between the box
tatuchka [14]

Answer:

Total work done is 2606.08 J.

Explanation:

Given :

Mass of box , m = 23 kg .

Force applied , F = 100 N .

Angle from horizon , \theta=39^o.

Coefficient of kinetic friction , \mu=0.16.

Distance travelled by box , d = 34 m .

Now ,

Total work done = work done by boy + work done by friction.

W=Fdcos\theta+f_sdcos\theta=Fd-\mu(mg) \\\\W=100\times cos39^o\times 34-0.16\times 23 \times 9.8 \\\\W=77.71\times 34-36.06=2606.08\ J.

Hence , this is the required solution.

6 0
3 years ago
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