The net ionic equation is the total ionic equation with the _________ removed.

1 answer:

7 0

The answer to the given question above is letter "D. spectator ions". The net ionic equation is the total ionic equation with the spectator ions removed. The spectator ions are the ions that appear in both sides of the balanced chemical reaction. This means that the spectator ions are not affected by the reaction.

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What is a scientific theory? A law that is always true a hypothesis about nature and educated guess based on observations an exp

egoroff_w [7]

Answer:

an explanation on how the natural world works

Explanation:

A scientific theory is simply an explanation into how the natural world works. Scientific theory is formulated after a series of hypothesis that has ascertained how true an observation is.

A theory is provides explanation into an observed feature. It can be disproved when new evidences are found. This brings about revision into scientific proofs.

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3 years ago

| The electric field 5.0 cm from a very long charged wire is (2000 N/C, toward the wire). What is the charge (in nC) on a 1.0-cm

Serggg [28]

Answer:

The charge is 0.056 nC.

Explanation:

Given that,

Electric field = 2000 N/C

Distance = 5.0 cm

We need to calculate the charge density

Using formula of charge density

$E=\dfrac{\lambda}{2\pi\times\epsilon_{0}r}$

$\lambda=2\pi\times\epsilon_{0}\times r\times E$

Put the value into the formula

$\lambda=2\pi\times8.85\times10^{-12}\times5.0\times10^{-2}\times2000$

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We need to calculate the charge in 1.0 cm

Using formula of charge

$Charge = \lambda\times\text{length of segment}$

$Charge =5.56\times10^{-9}\times1.0\times10^{-2}$

$Charge=0.056\times10^{-9}\ C$

$Charge=0.056\ nC$

Hence, The charge is 0.056 nC.

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3 years ago

A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its

lana [24]

At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

$B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }$