(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
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Step-by-step explanation:
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Answer:
Ratio = 3 : 2 and value of m = 5.
Step-by-step explanation:
We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.
Let us assume that it cuts the line in k : 1 ratio.
Then, the co-ordinates of P =
.
But,
= -6
i.e. -8k-3 = -6k-6
i.e. -2k = -3
i.e. 
So, the ratio is k : 1 i.e
i.e. 3 : 2.
Hence, the ratio in which P divides the line is 3 : 2.
Also,
= m where 
i.e. m = 
i.e. m = 
i.e. m = 
i.e. m = 5.
Hence, the value of m is 5.
Percent of decrease :
Original - New / Original
so...
80 - 52 / 80 ---->
28/80
.35 multiply by 100 to get percent
35% increase Hope I helped if you have any questions let me know! :)