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3 years ago

5

Write a real world situation that would representby the system y=3x +20 and y=5x + 10

1 answer:

ryzh [129]3 years ago

4 0

There are 2 car rental companies
the first one charges 3 dollars per day you drive plus a 20 dollar insurance fee

the second one charges 5 dollars per day and a 10 dollar insurance fee
y=cost
x=days

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Leo has a rectangular garden with a perimeter of 40 feet. The width of the garden is 8 feet. What is the length of the garden?

pishuonlain [190]

Answer:

5 feet

Step-by-step explanation:

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2 years ago

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3 years ago

What does p equal in the equation 84,000p + 36,000m = 1,962, 800

Alex_Xolod [135]

Answer:

p=−37m+70130

Step-by-step explanation:

Step 1: Add -36000m to both sides.

36000m+84000p+−36000m=1962800+−36000m

84000p=−36000m+1962800

Step 2: Divide both sides by 84000.

84000p84000=−36000m+196280084000

p=−37m+70130

3 0

2 years ago

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madam [21]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.

zloy xaker [14]

Answer:

$y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

$x={\pi}{4}$

Step-by-step explanation:

We are given that

$y'=\frac{2cos2x}{3+2y}$

y(0)=-1

$\frac{dy}{dx}=\frac{2cos2x}{3+2y}$

$(3+2y)dy=2cos2x dx$

Taking integration on both sides then we get

$\int (3+2y)dy=2\int cos 2xdx$

$3y+y^2=sin2x+C$

Using formula

$\int x^n=\frac{x^{n+1}}{n+1}+C$

$\int cosx dx=sinx$

Substitute x=0 and y=-1

$-3+1=sin0+C$

$-2=C$

$sin0=0$

Substitute the value of C

$y^2+3y=sin2x-2$

$y^2+3y-sin 2x+2=0$

$y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

Hence, the solution $y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

When the solution is maximum then y'=0

$\frac{2cos2x}{3+2y}=0$

$2cos2x=0$

$cos2x=0$

$cos2x=cos\frac{\pi}{2}$

$cos\frac{\pi}{2}=0$

$2x=\frac{\pi}{2}$

$x=\frac{\pi}{4}$

3 0

3 years ago