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expeople1 [14]
3 years ago
9

What is the actual name of compound-s that is used to treat arthritis?

Chemistry
1 answer:
Rudiy273 years ago
6 0
Reichsteins substance if I remember correctly.

Hope this helped! :)

- Juju
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The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i
Rus_ich [418]

Answer: a)  The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) concentration after 8.8 min:

8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}

\log\frac{0.25}{a-x}=0.15

\frac{0.25}{a-x}=1.41

(a-x)=0.17M

b) for concentration to decrease from 0.25M to 0.15M

t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20

t=687s

7 0
3 years ago
Convert 5.50 mol of MgO to g.
Fiesta28 [93]

Answer:

5.50 moles of magnesium oxide is 221.6742 grams

Explanation:

to do this you multiply the number of moles by the molar mass

7 0
2 years ago
Weathering is the process that takes place as rocks, and other parts of the geosphere, are??
olganol [36]
Breaking down that’s why they make land slides
5 0
3 years ago
What is the difference between the lithosphere and the crust?
Dmitrij [34]

Answer:

The answer is B "The lithosphere is characterized by its physical state while the crust is characterized by its composition (mostly oxygen, aluminum, and silicon)

8 0
3 years ago
An aqueous solution contains 1.00 g/L of a derivative of the detergent laurel alcohol. The osmotic pressure of this solution is
iVinArrow [24]

Answer:

mm = 1043.33 g/mol

Explanation:

osmotic pressure (π):

  • π = CbRT

∴ π = 17.8 torr = 0.0234 atm

∴ Cb: solute concentration

∴ T = 25°C = 298 K

∴ R = 0.082 atm.L/K.mol

⇒ Cb = π/RT

⇒ Cb = (0.0234 atm)/((0.082 atm.L/K.mol)(298 K))

⇒ Cb = 9.585 E-4 mol/L

molar mass (mm):

⇒ mm = (1.00 g/L)(L/9.585 E-4 mol)

⇒ mm = 1043.33 g/mol

7 0
3 years ago
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