Answer:
<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>
Explanation:
No. of moles = 
= 
= 0.001245 moles
Concentration of KHP (C1) in litres = n/v
= 
= 0.062 mol/L
We know that:
= 
where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.
Since mole ratio is 1 : 1.
1 mole of NaOH - 40g
0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g
⇒0.0498g of NaOH was used during the titration
<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>
<u><em>= 2.49g/L.</em></u>
It’s either the first or second one
I think it’s the first one - the outer cells of the blastocyst
The pressure, in mmHg, exerted by only the oxygen gas is 720.8 mmHg
<h3>Pressure of gas collected over water</h3>
The total pressure of a gas collected over water is given by P = P' + p where
- P = pressure of oxygen gas and
- p = vapour pressure of water at 25 °C = 25 mmHg
Making P' subject of the formula, we have
P' = P - p
Since the total pressure of oxygen plus water vapor is P = 745.8 mmHg, substituting the values of the variables into the equation, we have
P' = P - p
P' = 745.8 mmHg - 25 mmHg
P' = 720.8 mmHg
So, the pressure, in mmHg, exerted by only the oxygen gas is 720.8 mmHg
Learn more about pressure of gas collected over water here:
brainly.com/question/25815247
Answer:
285.6
Explanation:
(283.4×0.3460)+(284.7×0.2120)+(287.8×0.4420)
=285.6204
