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2 years ago

5

Explain why it is better to use data from multiple trials to determine the molarity of acetic acid rather than data from a singl

e trial

1 answer:

vivado [14]2 years ago

7 0

This is the answer, in the picture :)

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Can anyone answer this? (I thank)

Mamont248 [21]

CO2 will be the first to boil because it will be the first to warm up because it is the closest temperature to 0

4 0

2 years ago

True or False: Photosynthesis can happen anytime, regardless of the amount of reactants present or the presence of sunlight.

Arisa [49]

The answer is false .

3 0

2 years ago

Read 2 more answers

What discovery was made about particles with an accelerator in 1998

kramer

Answer/Explanation:

In June 1998 in Japan a scientist discovered that neutrinos (which is a type of particle) has weight, mass. This was later proven with some very convincing strong evidence.

<u><em>~ LadyBrain</em></u>

8 0

2 years ago

1. A mixture contains 8.00 g each of O2, CO2, and SO2 at STP. Calculate the volume of this mixture. Which of the gases would exe

Gekata [30.6K]

Answer:

Explanation:

mole of O₂ = $\frac{8}{32}$

= .25 moles

mole of CO₂

= $\frac{8}{44}$

= .1818 moles

moles of SO₂

$\frac{8}{64}$

= .125 moles

Total moles of gas

= .5568 moles.

total volume of gas mixture

= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)

= 12.47 liter.

gas will exert partial pressure according to their mole fraction

gas having greatest no of moles in the total mole will have greatest mole fraction so

O₂ will have greatest partial pressure.

7 0

2 years ago

At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c

ivolga24 [154]

<u>Answer:</u> The equilibrium concentration of bromine gas is 0.00135 M

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

$2BrCl\rightleftharpoons Br_2+Cl_2$

<u>Initial:</u> 0.02 0.03

<u>At eqllm:</u> 0.02-2x x 0.03+x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}$

We are given:

$K_c=0.141$

Putting values in above equation, we get:

$0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135$

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

8 0

3 years ago