Light as a wave
- Young's Double Slit Experiment.
- Davisson-Germer Experiment
Light as a particle
- Einsteins Photoelectric Effect Phenomenon
- Diffraction Phenomenon of Particles
<h2>Define the following terms:-</h2><h3>
1)Photoelectric Effect</h3>
Electrons are released when a material is exposed to electromagnetic radiation, such as light, and this is known as the photoelectric effect. These electrons are referred to as photoelectrons.
<h3>
2)Diffraction </h3>
When a wave hits a wall or an opening, several phenomena known as diffraction take place. It is described as the interference or bending of waves through an aperture into the region of the geometric shadow cast by the obstruction or aperture.
<h3>3)
Davisson-Germer Experiment</h3>
In the Davisson-Germer experiment, conducted by Clinton Davisson and Lester Germer between 1923 and 1927 at Western Electric (later Bell Labs), electrons scattered by a nickel-metal crystal's surface showed a diffraction pattern. This was an experimental turning point in the development of quantum mechanics and supported the wave-particle duality concept first put forth by Louis de Broglie in 1924.
<h3>4)
Young's Double Slit Experiment.</h3>
One of the most significant physics experiments was Young's Double Slit experiment. Thomas Young directed it in 1801. Despite the fact that Huygens' experiment had demonstrated that light has a wave character, the light at the time was still thought of as a beam of particles due to Newton's renown.
Learn more about the photoelectric effect here:-
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Oh wow , what grade are you in ukliblo ?
One of the most powerful laws in physics is the law of momentum conservation. ... For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
Answer:
(1) The sample should not be large, because a large sample would produce a higher and broader mp range.
(2) The rate of heating does not matter.
Explanation:
(1) The sample should not be large, because a large sample would produce a higher and broader mp range, because varying temperature range across the body will lead to inaccurate determination of melting point.
(2) In principle, the melting temperature is INDEPENDENT (not dependent) on the heating rate. so in other words, altering the heating rate does not affect the measure of melting point.
Answer:
D. Water and Carbondioxide
Explanation:
Combustion of organic compounds in the presence of excess Oxygen will liberate carbondioxide (CO2) and water vapour (H2O). This is an exothermic reaction because heat is liberated to the surroundings.
CnH2n+1OH(aq) + (3/2*n)O2(g) --> nCO2(g) + (n + 1)H2O(g)
Addition of Oxygen can also be termed as a redox reaction. In this case, alcohols are oxidised while the Oxygen is reduced.
Example, (propanol)
C3H7OH(aq) + 9/2O2(g) --> 3CO2(g) + 4H2O(g)
