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3 years ago

The denver public library wants to estimate the percent

Mathematics

1 answer:

zlopas [31]3 years ago

6 0

Is there more information then that

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How can I work this problem in adding integers with counters 5 + (-7)

Monica [59]

$\huge\mathsf\green{Answer}$

$5 + ( - 7) \\ 5 - 7 = - 2$

<h3>hope it would be helpful </h3>

4 0

3 years ago

The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i

hram777 [196]

In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78

6 0

3 years ago

Solve the following system of equations by elimination

olya-2409 [2.1K]

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

-x -2y = 11

-1 -(2*-6) = 11

-1 -(-12) = 11

-1 + 12 = 11

5 0

2 years ago

Help Find the lateral area of this pyramid whose base is an equilateral triangle. Its slant height is 14 ft and the length of ea

kenny6666 [7]

Answer:

168 ft²

Step-by-step explanation:

The equation for the lateral area of a square pyramid is LA = (Pl/2)

Plug in the values LA = (24(14)) / 2

LA = 336/2

LA = 168 ft²

8 0

4 years ago

What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

xxMikexx [17]

Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure

3 0

3 years ago

Read 2 more answers