Okay. In my opinion, all the class has to do is simplify the expressions and compare. But they want to substitute instead.
Well then.
First, let's notice that these are linear expressions, meaning that if they are equivalent then all their values match up.
Number 1 is not a good one. Just because they're both positive doesn't mean anything; they have to be <em>the same.</em>
This also eliminates 3.
Number 2 is a good one, but it's not as reliable. If, for instance, the two expressions are <em>not </em>equivalent and you get lucky enough to pick that one value they intersect at (or have in common), then you'd be wrong when you say they are equivalent.
Number 4 makes the most sense because if both expressions are equivalent, then every value matches up. If not, then only one will. So having two values to substitute will most definitely answer the class question.
Hope this helps, let me know if I messed up! ;)
Answer:
The possible length of the triangle =
1) (1inches, 196inches)
2) (2incheq, 98inches)
3) (4inches , 49 inches)
4) (7 inches , 28 inches)
Step-by-step explanation:
We are told the above Triangle is not an Isosceles Triangle
Hence, we assume it is a right angle triangle
The area of a triangle is = 1/2 × Base × Height
= let us represent Base and Height = x
Hence:
1/2 × x × x = 98
x² /2 = 98
Cross Multiply
x² = 98 × 2
x² = 196
Step 2
We find the factors of 196
1× 196 = 196 (1, 196)
2 × 98 = 196 (2, 98)
4 ×49 = 196 (4, 49)
7 × 28 = 196 (7, 28)
Therefore, all the possible length of the triangle =
1) (1inches, 196inches)
2) (2incheq, 98inches)
3) (4inches , 49 inches)
4) (7 inches , 28 inches)
Answer:
C
Step-by-step explanation:
Volume of a pyramid = 1/3 base area * height
= 1/3 (8 * 10)(12)
Answer: 49 in^2
Step-by-step explanation:
Trapezoid area formula = (a+b/2) x h
So...
(5+9/2) x 7
= 49 in^2
Answer:
r = 5sec(θ)
Step-by-step explanation:
The usual conversion is ...
y = r·sin(θ)
x = r·cos(θ)
__
The second of these can be used here.
r·cos(θ) -5 = 0
r·cos(θ) = 5
r = 5/cos(θ) = 5sec(θ)
A suitable polar equation is ...
r = 5sec(θ)
