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joja [24]
2 years ago
5

the combined area of two squares is 45 square centimetres each side is twice as long as a side of the other square what length o

f each side of the larger square
Mathematics
1 answer:
Ostrovityanka [42]2 years ago
4 0

Answer:

Let the side of  one square be x.    Area = x*x = x²

Then the side of other square  would be 2x ,   Area = 2x*2x = 4x²

Combined area = x² + 4x²  = 5x²

This combined area = 45 cm²

you simplify

Therefore  5x²  = 45   Divide both sides by 5

                 x²  =  45/5

                 x²  = 9        Take square root of both sides

                 x   =  √9

                 x  = 3

Length of larger square is 2x  = 2*3 = 6 cm

Length of larger square = 6cm

Step-by-step explanation:

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Solve the problem given below
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<u>Answer</u>

<em>12 in by 12 in</em>

<u>Explanation</u>

The original length = x

This makes the length of the cube made to be = x - (2×2)

                                                                               = (x - 4) in

height of the cube = 2 in

Volume of the cube = (x - 4) × (x - 4) × 2 = 128

                                 = (x² - 8x + 16) × 2 = 128

                                = 2x² - 16x + 32 = 128

                                 = 2x² - 16x + 32- 128=0

                                 = 2x² - 16x - 96 = 0

                                 = x² - 8x - 48 = 0

lets use the factor method to solve the quadrilatic equation above,

x² - 8x - 48 = 0

proctuct = -48

sum = -8

The two factors are; -12 and 8.

(x + 8)(x - 12) = 0

So the value of x are 12 and -8.  Since x is a length, it can not be negative.

∴ x = 12 in.

The original dimensions of the sheet are <em>12 in by 12 in</em>.

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Step-by-step explanation:

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