The equivalence point during a weak acid-strong base titration, the pH will be determined from ___.
1 answer:
Answer:
The pH will be determined from the equivalence point i.e. "greater than 7."
Explanation:
In the titration between the weak acid along with a strong base, the conjugate base of the weak acid will probably make the pH at the equivalence point which is greater than 7. Hence, an indicator is required to know the pH change at this range. Basically phenolphthalein is used as an indicator in this case. The weak acid will turn into bright pink. After this if excess of the hydrogen ions are added then the position of the equilibrium will be shifted to the left and make the indicator colorless.
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Answer:
i. Keq=4157.99.
ii. More hydrogen sulfide will be produced.
Explanation:
Hello,
i. In this case, for the concentrations at equilibrium on the given chemical reaction, the equilibrium constant results:
ii. Now, by means of the Le Chatelier's principle, the addition of a reactant shifts the reaction towards products, it means that more hydrogen sulfide will be produced in order to reach equilibrium.
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Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.
See attached figure for the structure.
Vanillin have 3 functional groups:
1) aldehyde group: R-HC=O, in which the carbon is double bonded to oxygen
2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring
3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons
Now for the hybridization we have:
The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.
The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a <u>sp³</u> hybridization because they are involved only in single bonds.
