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dlinn [17]
4 years ago
7

How many formula units make up 11.2 g of Magnesium Chloride MgCl2?

Chemistry
2 answers:
ki77a [65]4 years ago
8 0
Solved:
Molar mass MgCl2 = 24.31 + 35.45 x 2 = 95.21g/mol 
One mole is equal to 6.022*10^23 formula units
<span>Each mole of MgCl2 has 6.022 x 10²³ MgCl2 molecules (formula units) </span>

<span>so number of formula units in the MgCl2 sample =
11.2 g MgCl2 * [1 mol / 95.21 g] x [6.022 x 10²³ formula units / mol] </span>

<span>= 7.0 x 10^22 MgCl2 formula units</span>
deff fn [24]4 years ago
4 0

Answer:

7.08*10^{22} formula units

Explanation:

The first step in solving this question is to find the number of moles of magnesium chloride in 11.2 g.

number of moles = \frac{mass}{molar mass}=\frac{11.2g}{95.211g/mol}= 0.117633mol

The second step is to remember Avogadro's number. In one mole of magnesium chloride, there are 6.022*10²³ formula units. So how many formula units are there in 0.117633 moles?

no. of formula units=0.117633 mol*6.022*10^{23} formula units/mol =7.08*10^{22} formula units

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