Answer:
Explanation:
Given
Force=18lb
extension=8in
Using Hooke's law to get the spring constant(k)
F=ke
Then,
K=f/e
K=18/8
K=2.25lb/in
Work done by spring is given by
W=1/2Fe
Or W=1/2ke²
Then,
Work done in stretching the spring to 14in
W=1/2ke²
W=0.5×2.25×14²
W=220.5lbin
1 Inch-pounds Force to Joules = 0.113J
Then, to joules
W=0.133×220.5
W=29.33J
We need first to use the formula F=m(a+g), m iis the total mass, a is the acceleration, g is gravity pulling the blocks. So the procedure will be
<span>m=2kg(both blocks)+500g(both ropes) → m=2.5kg </span>
<span>a=3.00m/s^2 </span>
<span>g=9.8m/s^2 </span>
<span>F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N
To calculate the tension at the top of rope 1 you need to use the formula </span>T=m(a+g) so it will be <span>T=m(a+g) → T=1.5kg(12.8m/s^2) → T=19.2N
</span>We can now calculate the tension at the bottom of rope 1 using the formula: <span>T=m(a+g) → T=1.25kg(12.8m/s^2) → T=16N
</span>Now to find the tension at the top of rope 2 we do it like this:
<span>T=m(a+g) → T=.25kg(12.8m/s^2) → T=3.2</span>
Answer:
v = -10⁵ m/s
Explanation:
given,
speed of asteroid,v' = 100 m/s
mass of superman = m
mass of asteroid,M = 1000 m
recoil velocity of superman,v= ?
using conservation of momentum.
m u + M u' = m v + M v'
initial velocity of asteroid and superman is equal to zero
0 + 0 = m v + 1000 m x 100
m v = -100000 m
v = -10⁵ m/s
superman's velocity after throwing the asteroid is equal to v = -10⁵ m/s
