Answer:
a.After
second Mr Comer's speed
![1.7 m/s](https://tex.z-dn.net/?f=1.7%20m%2Fs)
b.Distance travelled by Mr.Comer in
seconds
![18.75\ m](https://tex.z-dn.net/?f=18.75%5C%20m)
Explanation:
a. Lets recall our first equation of motion ![V_{f} =V_{i} + at](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3DV_%7Bi%7D%20%2B%20at)
Now we know that
,
and
![t = 15 \ sec](https://tex.z-dn.net/?f=t%20%3D%2015%20%5C%20sec)
Plugging the values we have.
![V_{f} =V_{i} + at](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3DV_%7Bi%7D%20%2B%20at)
![V_{f} =0.8 + 0.06 \times 15](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D0.8%20%2B%200.06%20%5Ctimes%2015)
![V_{f} =0.8+ 0.9](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D0.8%2B%200.9)
![V_{f} =1.7 m/s](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D1.7%20m%2Fs)
Then Mr.Comer's speed after
sec
![1.7ms^-1](https://tex.z-dn.net/?f=1.7ms%5E-1)
b.
Lets find the distance and recall our third equation of motion.
![V_{f} ^2-V{i}^2 = 2as](https://tex.z-dn.net/?f=V_%7Bf%7D%20%5E2-V%7Bi%7D%5E2%20%3D%202as)
So
distance covered.
Dividing both sides with 2a we have.
![\frac{V_{f} ^2-V{i}^2}{2a} = 2as](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7Bf%7D%20%5E2-V%7Bi%7D%5E2%7D%7B2a%7D%20%3D%202as)
Plugging the values.
![\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as](https://tex.z-dn.net/?f=%5Cfrac%7B%281.7%29%5E2-%280.8%29%5E2%7D%7B2%5Ctimes0.06%7D%20%3D%202as)
![s= 18.75\ m](https://tex.z-dn.net/?f=s%3D%2018.75%5C%20m)
So Mr.Comer will travel a distance of
.
The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.
perimeter of a rectangle = 2(L+B)
90=2(L+B)
90/2=L+B
45=L+B
Answer:
The average speed for the whole journey is 49.5 miles per hour.
Explanation:
Step 1 :
Here, both the ways, he covers the same distance. Then, the formula to find average speed is
= 2xy / (x+y)
Step 2 :
x ----> Rate at which he travels from New York to Washington
x = 45
y ----> Rate at which he travels from New York to Washington
y = 55
Step 3 :
So, the average speed is
= (2 ⋅ 45 ⋅ 55) / (45 + 55)
= 4950 / 100
= 49.5
Answer:
Regions near rivers have water surfaces that rapidly change in temperature from cold to hot.
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