Answer:
4.88 x 10∧-8 sec
Explanation:
A ball whose mass is 1.9 kg is suspended from a spring whose stiffness is 8.0 N/m. The ball oscillates up and down with an ampli
1 answer:
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Answer:
a) At the instant when you measure that the space racer has traveled 1.22 x 108 m past you the time read by the race pilot is 0.478 s
b) When the race pilot reads the value of her time calculated, in part on her timer(0.478 s), she measure the distance of the space utility vehicle from her to be 6.43 × 10⁷ m
c) The instant when the race pilot reads the 0.478 s value calculated in part a) on her timer, the pilot of the space utility vehicle reads 0.478 s
Explanation:
To solve the question, we take account of the theory of relativistic motion as follows
Let Δt be the time duration observed by the race pilot and
Let Δt₀ is the time interval measured by the pilot in the space utility vehicle.
With u, being the velocity of the space racer and c, the speed of light.
Therefore by Lorentz factorization, we have
(a) When the space racer has traveled a distance of 1.22 x 10⁸ m past then we have
= 0.478 s
Since , we have
= 0.252 s
(b) The distance measured by the racer is given as
d = Δt₀ × 0.850 × c = 0.252 × 0.850 × 3.0 x 10⁸ m/s = 6.43 × 10⁷ m
(c) The time red from within the utility vehicle is given as;
.