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kompoz [17]
3 years ago
10

A ball whose mass is 1.9 kg is suspended from a spring whose stiffness is 8.0 N/m. The ball oscillates up and down with an ampli

tude of 17 cm. Part 1 (a) What is the angular frequency? ω= radians/s the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.
Physics
1 answer:
MArishka [77]3 years ago
4 0

Answer:

2.05 radians/s

Explanation:

This is a simple harmonic motion. The angular frequency of a loaded spring is given by

\omega = \sqrt{\dfrac{k}{m}}

where k is the spring constant and m is the mass on the spring.

Using the known values,

\omega = \sqrt{\dfrac{8}{1.9}} = 2.05

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Convert 56 kilometers to inches
svlad2 [7]
The conversion for km to inches is:

1km=39370.1in

Now we can solve for 56 km..

56km=39370.1*56
56km=<span> 2204725.6in

Answer=2,204,725.6in</span>
7 0
3 years ago
What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make
Sonja [21]

Answer:

The transverse wave

Explanation:

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3 years ago
Calculate the work done if a boy lifts a bag of cement 500N to the floor of a lorry 2.5m above the ground
eduard

Answer:

W = 1250 J = 1.25 KJ

Explanation:

The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:

W = P.E\\W = mgh

where,

W = Work done = ?

mg = W = weight of cement = 500 N

h = height covered = 2.5 m

Therefore,

W = (500\ N)(2.5\ m)

<u>W = 1250 J = 1.25 KJ</u>

4 0
3 years ago
An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due
Nezavi [6.7K]

Answer:

The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.

Explanation:

We can use Newton's Law of Universal Gravitation:

  • \displaystyle F_g=G\frac{Mm}{r^2}

Let's look at Newton's 2nd Law:

  • F=ma

We can set these equations equal to each other:

  • \displaystyle G\frac{Mm}{r^2} =ma

The mass of the second mass (astronaut) cancels out. We are left with:

  • \displaystyle G\frac{M}{r^2} =a

We are solving for the radius of the new planet, so we can rearrange the equation:

  • \displaystyle r=\sqrt{\frac{GM}{a} }

Substitute in our known values given in the problem (<u><em>G = 6.67 * 10⁻¹¹ </em></u><em> ; </em><u><em>M = 7.5 * 10²³</em></u><em> ; </em><u><em>a = 12</em></u>).

  • \displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }
  • r=2.04 \times 10^6

The radius of the new planet is ~2.04 * 10⁶ m.

3 0
2 years ago
Please help I need help this is so confusing to me
spayn [35]
C. increased stirring i think
7 0
3 years ago
Read 2 more answers
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